The value of the angle ∠AVB is 53°, side VB = 132.83 m, side OV = 119 m
<h3>How to find the side length from bearings?</h3>
8) From the given triangle we see that;
∠VAO = 37°
∠VBO = 64°
∠VOA = 90°
a) Now, we know that sum of angles in a triangle is 180°. Thus, for triangle AVO, we can say that;
∠VAO + ∠VOA + ∠AVB = 180°
37 + 90 + ∠AVB = 180°
∠AVB = 180° - 127°
∠AVB = 53°
b) Using triangle rules we can say that;
tan 64 = VO/BO
Similarly, we can say that;
tan 37 = VO/(100 + BO)
Dividing both equations gives;
tan 64/tan 37 = (100 + BO)/BO
2.72BO = 100 + BO
1.72BO = 100
BO = 58.14 m
Using trigonometric ratio;
58.14/VB = cos 64
VB = 132.83 m
c) OV/132.83 = sin 64
OV = 132.83 * sin 64
OV = 119 m
Read more about Side lengths from bearings at; brainly.com/question/23427938
#SPJ1
