Question

Pls solve question 8

Answer 1

The value of the angle ∠AVB is 53°, side VB = 132.83 m, side OV = 119 m

How to find the side length from bearings?

8) From the given triangle we see that;

∠VAO = 37°

∠VBO = 64°

∠VOA = 90°

a) Now, we know that sum of angles in a triangle is 180°. Thus, for triangle AVO, we can say that;

∠VAO + ∠VOA  + ∠AVB = 180°

37 + 90 + ∠AVB = 180°

∠AVB = 180° - 127°

∠AVB = 53°

b) Using triangle rules we can say that;

tan 64 = VO/BO

Similarly, we can say that;

tan 37 = VO/(100 + BO)

Dividing both equations gives;

tan 64/tan 37 = (100 + BO)/BO

2.72BO = 100 + BO

1.72BO = 100

BO = 58.14 m

Using trigonometric ratio;

58.14/VB = cos 64

VB = 132.83 m

c) OV/132.83 = sin 64

OV = 132.83 * sin 64

OV = 119 m

Read more about Side lengths from bearings at; brainly.com/question/23427938

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