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Serggg [28]
2 years ago
14

Suppose log subscript a x equals 2, space log subscript a y equals 5, and log subscript a z equals short dash 3. Find the value

of the following expression. log subscript a open parentheses fraction numerator x y cubed over denominator z squared end fraction close parentheses
Mathematics
1 answer:
sineoko [7]2 years ago
3 0

The value of the logarithmic expression  \log _a (\frac{x^3y}{z^4} ) is 24.

Given the following logarithmic expressions \log _ax = 3, \log _ay = 7, \log _az = -2 , we are to find the value of \log _a (\frac{x^3y}{z^4} )

from the above \log _ax = 3, x = a^3

\log _ay = 7, y = a^7

Substituting x = a^3, y = a^7  and z = a^{-2} into the log function\log _a (\frac{x^3y}{z^4} )  we will have;

\log _a (\frac{x^3y}{z^4} )\\=\log _a (\frac{(a^3)^3 \times a^7}{(a^{-2})^4} )\\= \log _a (\frac{a^9 \times a^7}{a^-^8} )\\= \log _a (\frac{a^1^6}{a^-^8} )\\= \log _a (\frac{x^3y}{z^4} )\\= \log _a a^2^4\\= 24 \log _a a\\= 24 \times 1\\= 24

Hence, the value of the logarithmic expression is 24

<h3>What is logarithmic expression?</h3>
  • In an exponential equation, the variable is expressed as an exponent. An equation using the logarithm of an expression containing a variable is referred to as a logarithmic equation.
  • Check to determine if you can write both sides of the equation as powers of the same number before you attempt to solve an exponential equation.

To learn more about logarithmic expression with the given link

brainly.com/question/24211708

#SPJ4

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1/2x+4=20 solve for x.. Help?
hichkok12 [17]

Answer: 32

Step-by-step explanation: ok so here is what i do for those I grab a caculator (desmos online caculator i like to use but not required) then ill do (1/2×x)+4 but then once i write that i go back to the x delete the x and keep putting random numbers in higher and higher by one till the i get the answer (example: for this one i wrote that than i removed the x in it and did 1/2×5+4 then when that did not equal 20 i turned the 5 into a 6 then 6 was wrong so 7, then 8, then i just skipped to 20 then 20 was still wrong so skipped to 30, 30 was also wrong but CLOSE so then i tried 31 then 32 till the answer was 20 and when i did 32 it did say 20) hopes this helps

7 0
3 years ago
Read 2 more answers
There are 1,000 cans of cat food produced daily at a factory. in the meeting last week, the
BaLLatris [955]

Using the binomial distribution, it is found that the true statement related to the number of cans of cat food the company expects to be dented is given by:

B. The factory can expect to have an average of 50 cans dented in a day.

<h3>What is the binomial probability distribution?</h3>

It is the probability of exactly<u> x successes on n repeated trials, with p probability</u> of a success on each trial.

The expected value of the binomial distribution is:

E(X) = np

In this problem, we have that there are 1000 cans, each with a probability of 1/20 of being dented, hence:

n = 1000, p = 1/20 = 0.05.

The expected value is then given by:

E(X) = np = 1000 x 0.05 = 50.

Researching the problem on the internet, the correct option is given by:

B. The factory can expect to have an average of 50 cans dented in a day.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

4 0
2 years ago
Can you tell me how to calculate R for below Matrix ?
scoray [572]

Answer:

The rank of the matrix is 3.

Step-by-step explanation:

Consider the prided information.

x=\begin{bmatrix}x_1\\ x_2\\ x_3\end{bmatrix}=\begin{bmatrix}9&2&6&5&8\\ 12&8&6&4&10\\ 3&4&0&2&1\end{bmatrix}

Reduce the matrix in row echelon form as shown:

R_1\:\leftrightarrow \:R_2\begin{bmatrix}12&8&6&4&10\\ 9&2&6&5&8\\ 3&4&0&2&1\end{bmatrix}\\

R_2\:\leftarrow \:R_2-\frac{3}{4}\cdot \:R_1\ and\ R_3\:\leftarrow \:R_3-\frac{1}{4}\cdot \:R_1\\\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&2&-\frac{3}{2}&1&-\frac{3}{2}\end{bmatrix}

R_3\:\leftarrow \:R_3+\frac{1}{2}\cdot \:R_2\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&0&-\frac{3}{4}&2&-\frac{5}{4}\end{bmatrix}

R_2\:\leftarrow \:R_2-\frac{3}{2}\cdot \:R_3\ and\ R_1\:\leftarrow \:R_1-6\cdot \:R_3\\\begin{bmatrix}12&8&0&20&0\\ 0&-4&0&6&-2\\ 0&0&1&-\frac{8}{3}&\frac{5}{3}\end{bmatrix}\\R_2\:\leftarrow \:-\frac{1}{4}\cdot \:R_2\ , \ R_1\:\leftarrow \:R_1-8\cdot \:R_2\ and\ \:R_1\:\leftarrow \frac{1}{12}\cdot \:R_1\\\begin{bmatrix}1&0&0&\frac{8}{3}&-\frac{1}{3}\\ 0&1&0&-\frac{3}{2}&\frac{1}{2}\\ 0&0&1&-\frac{8}{3}&\frac{5}{3}\end{bmatrix}

The rank of a matrix is the number of non zeros rows.

Thus, the rank of the matrix is 3.

6 0
3 years ago
If you have lived for a million seconds, how many birthdays have you had?
Romashka [77]

A million seconds is not that long.  My next birthday is in  1,296,000  seconds
from now, and I have already lived more than  2.3 billion seconds !

(1,000,000 seconds) x (1 day / 86,400 seconds) =

                 11days 13hours 46minutes 40seconds .

It's possible that you might have one birthday within that length of time,
but it's not guaranteed.  It would have to be the RIGHT million seconds.

If that's been your whole life so far ... you are 1 million seconds old ..,
then you have not had your first birthday yet.

7 0
3 years ago
Read 2 more answers
2) the quotient of 14 and 7
tamaranim1 [39]

Answer:

The quotient of 7 and 14 is 2..

4 0
3 years ago
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