They could get 2 boxes of candy because they total with drinks would be 34.50 so 2 boxes of candy every thing would come out to 38.50
24% because you would make a ratio like x/100= 2,160/9000. So basically the x is the percentage you need, 100 is just an easy factorable percent, and 2,160 is the wheat bread and 9000 is all the bread. Basically what you do with this ratio is you cross multiply. This means you multiply 2,160 by 100 and divide by 9000 and that’s your percent
Answer:
b = 60
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
b² + 63² = 87²
b² + 3969 = 7569 ( subtract 3969 from both sides )
b² = 3600 ( take the square root of both sides )
b =
= 60
Answer:
![z=\frac{510-520}{\frac{90}{\sqrt{100}}}= -1.11](https://tex.z-dn.net/?f=%20z%3D%5Cfrac%7B510-520%7D%7B%5Cfrac%7B90%7D%7B%5Csqrt%7B100%7D%7D%7D%3D%20-1.11)
And we can find the probability using the normal standard distribution table and with the complement rule we got:
![P(z](https://tex.z-dn.net/?f=P%28z%3C-1.11%29%3D%200.1335)
Step-by-step explanation:
For this problem we have the following parameters:
![\mu = 520, \sigma = 90](https://tex.z-dn.net/?f=%20%5Cmu%20%3D%20520%2C%20%5Csigma%20%3D%2090)
We select a sample size of n =100 and we want to find this probability:
![P(\bar X](https://tex.z-dn.net/?f=%20P%28%5Cbar%20X%20%3C510%29%20)
The distribution for the sample mean using the central limit theorem would be given by:
![\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})](https://tex.z-dn.net/?f=%5Cbar%20X%20%5Csim%20N%28%5Cmu%2C%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%29)
And we can solve this problem with the z score formula given by:
![z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=%20z%3D%5Cfrac%7B%5Cbar%20X%20-%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
And if we find the z score formula we got:
![z=\frac{510-520}{\frac{90}{\sqrt{100}}}= -1.11](https://tex.z-dn.net/?f=%20z%3D%5Cfrac%7B510-520%7D%7B%5Cfrac%7B90%7D%7B%5Csqrt%7B100%7D%7D%7D%3D%20-1.11)
And we can find the probability using the normal standard distribution table and with the complement rule we got:
![P(z](https://tex.z-dn.net/?f=P%28z%3C-1.11%29%3D%200.1335)
Answer:
7
Step-by-step explanation: