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-Dominant- [34]
2 years ago
14

14. How do digital libraries address the problem of digital exclusion?

Computers and Technology
1 answer:
loris [4]2 years ago
3 0

The digital libraries address the problem of digital exclusion by: They reach out to people who need technology and help teach them digital literacy skills.

<h3>What does it mean to be digitally excluded?</h3>

The  digital exclusion  is known to be also as digital divide and this is known to be where a part of the population is known to possess a continuous and unequal access and capacity in regards to the use Information and Communications Technologies (ICT),

Note that IT are very essential for all to be fully participated  in the society and the digital libraries address the problem of digital exclusion by: They reach out to people who need technology and help teach them digital literacy skills.

Learn more about digital exclusion from

brainly.com/question/7478471

#SPJ1

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Order the steps for using the Rules Wizard to create an email rule.
Serhud [2]

Answer:

select the home tab and click rules button

select manage rules and alerts

click new rule and select a template

edit a description of the rule by adding values

make any exceptions and name the rule

Explanation:

just took it on edg

6 0
3 years ago
When the logging and managing information flow between management hosts and the managed devices travels on a dedicated managemen
kompoz [17]

What must be considered is the number of IPs that are allowed to access the management network.

We can arrive at this answer because:

  • During the management of information flow, it is necessary to guarantee the security of the system, preventing intruders from attacking.
  • This can be done by restricting authorized IPs to access the management interface.
  • This type of security measure is often neglected in systems that use a dedicated management network, as this type of network can only be accessed by a single device in the same VLAN.

However, the IPs restriction must be considered even in this system, as there are software that can provoke invasions that cause the leak of shared information.

You can find more information about software here:

brainly.com/question/24032221

4 0
3 years ago
Write the prototype for a function named showSeatingChart that will accept the following two-dimensional array as an argument. c
barxatty [35]

Answer:

See explaination

Explanation:

void showSeatingChart(string seatingChart[20][40], const int ROWS, const int COLS){

for(int i = 0;i<ROWS;i++){

for(int j = 0;j<COLS;j++){

cout<<seatingChart[i][j]<<" ";

}

cout<<endl;

}

}

4 0
3 years ago
An object is identified by its<br>characteristics<br>state<br>class<br>attribute​
goldfiish [28.3K]

Answer:

Characteristics is the correct answer to the given question .

Explanation:

The main objective of object is for accessing the member of class .When we have to access the member of class we can create the object of that class The object  is is identified by there characteristics.The characteristics describe the behavior and state of a class.

  • With the help of class and object we can implement the real world concept .
  • The object is the run time entity of a class where as the class is physical entity .
  • Without the object we can not implemented the object oriented programming.
  • All the other option are not correct for the object because they are not described the identification of object .
3 0
3 years ago
Write a program that will ask for the user to input a filename of a text file that contains an unknown number of integers. And a
Ratling [72]

Answer: Provided in the explanation section

Explanation:

Code provided below in a well arranged format

inputNos.txt

70

95

62

88

90

85

75

79

50

80

82

88

81

93

75

78

62

55

89

94

73

82

___________________

StandardDev.java

import java.io.File;

import java.io.FileNotFoundException;

import java.util.Scanner;

public class StandardDev {

public static void main(String[] args) {

//Declaring variables

String filename;

int count = 0, i = 0;

Scanner sc1 = null;

int min, max;

double mean, stdDev;

int nos[] = null;

/*

* Creating an Scanner class object which is used to get the inputs

* entered by the user

*/

Scanner sc = new Scanner(System.in);

//Getting the input entered by the user

System.out.print("Enter the name of the filename :");

filename = sc.next();

try {

//Opening the file

sc1 = new Scanner(new File(filename));

//counting no of numbers in the file

while (sc1.hasNext()) {

sc1.nextInt();

count++;

}

sc1.close();

sc1 = new Scanner(new File(filename));

//Creating an Integer based on the Count

nos = new int[count];

//Populating the values into an array

while (sc1.hasNext()) {

nos[i] = sc1.nextInt();

i++;

}

sc1.close();

//calling the methods

min = findMinimum(nos);

max = findMaximum(nos);

mean = calMean(nos);

stdDev = calStandardDev(nos, mean);

//Displaying the output

System.out.println("Read from file :" + count + " values");

System.out.println("The Minimum Number is :" + min);

System.out.println("The Maximum Number is :" + max);

System.out.printf("The Mean is :%.2f\n", mean);

System.out.printf("The Standard Deviation is :%.2f\n", stdDev);

} catch (FileNotFoundException e) {

e.printStackTrace();

}

}

//This method will calculate the standard deviation

private static double calStandardDev(int[] nos, double mean) {

//Declaring local variables

double standard_deviation = 0.0, variance = 0.0, sum_of_squares = 0.0;

/* This loop Calculating the sum of

* square of eeach element in the array

*/

for (int i = 0; i < nos.length; i++) {

/* Calculating the sum of square of

* each element in the array    

*/

sum_of_squares += Math.pow((nos[i] - mean), 2);

}

//calculating the variance of an array

variance = ((double) sum_of_squares / (nos.length - 1));

//calculating the standard deviation of an array

standard_deviation = Math.sqrt(variance);

return standard_deviation;

}

//This method will calculate the mean

private static double calMean(int[] nos) {

double mean = 0.0, tot = 0.0;

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Calculating the sum of all the elements in the array

tot += nos[i];

}

mean = tot / nos.length;

return mean;

}

//This method will find the Minimum element in the array

private static int findMinimum(int[] nos) {

int min = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] < min)

min = nos[i];

}

return min;

}

//This method will find the Maximum element in the array

private static int findMaximum(int[] nos) {

int max = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] > max)

max = nos[i];

}

return max;

}

}

_____________________

Output:

Enter the name of the filename :inputNos.txt

Read from file :22 values

The Minimum Number is :50

The Maximum Number is :95

The Mean is :78.45

The Standard Deviation is :12.45

cheers i hope this helped !!!

7 0
4 years ago
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