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andrew11 [14]
2 years ago
13

A client wants to know the total addressable market for mattress sales in New York City. Without calculating the actual number,

which type of statement below would best satisfy the client’s request? The total addressable market is $540 million annually. The total addressable market is everyone who needs to replace or buy new bedroom furniture. The total addressable market is 1.1 million bed frames. The total addressable market is $500 per mattress.
SAT
1 answer:
Stella [2.4K]2 years ago
6 0
Its the second one i think. It isn't calculating any actual number, it is giving a sort of broad answer of everyone that needs it new or replaced
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2.17 LAB: Word frequencies - methods Write a program that reads a list of words. Then, the program outputs those words and their
pickupchik [31]

Using the knowledge in computational language in JAVA it is possible to write a code that reads a list of words.

<h3>Writting the code in JAVA:</h3>

<em>import java.util.*;</em>

<em>//class name LabClass</em>

<em>public class LabClass{</em>

<em>    //function getFrequencyOfWord with array wordList, ListSize and currWord as parameter</em>

<em>    public static int getFrequencyOfWord(String[] wordsList, int ListSize, String currWord){</em>

<em>        int frequency = 0;</em>

<em>        //for loop for iteration </em>

<em>        for(int i=0; i<ListSize; i++){</em>

<em>            //if current word matches with words present in list</em>

<em>            //then increase the frequency by 1</em>

<em>            if(wordsList[i].compareTo(currWord)==0){</em>

<em>                frequency++;</em>

<em>            }</em>

<em>        }</em>

<em>        //return frequency at last </em>

<em>        return frequency;</em>

<em>    }</em>

<em>    //main function </em>

<em>    public static void main(String[] args) {</em>

<em>        //creating object of Scanner class </em>

<em>        Scanner sc = new Scanner(System.in);</em>

<em>        int size;</em>

<em>        //asking user to input size of list </em>

<em>        System.out.println("Enter the size of list :");</em>

<em>        size = sc.nextInt();</em>

<em>        //creating array of same size as user input size</em>

<em>        String[] wordList = new String[size];</em>

<em>        sc.nextLine();</em>

<em>        //asking user to input array elements </em>

<em>        System.out.println("Enter list elements one by one :");</em>

<em>        for(int i =0; i<size; i++)</em>

<em>        {</em>

<em>            wordList[i] = sc.nextLine();</em>

<em>        }</em>

<em>        System.out.print("\n");</em>

<em>        sc.close();</em>

<em>        //calling function getFrequencyOfWord in every iteration by passing</em>

<em>        //required arguments to it </em>

<em>        for(int i=0; i<size; i++)</em>

<em>        {</em>

<em>            String currWord = wordList[i];</em>

<em>            int count = getFrequencyOfWord(wordList, size, currWord);</em>

<em>            //printing result </em>

<em>            System.err.println(currWord + " : " + count);</em>

<em>        }</em>

<em>    }</em>

<em>}</em>

See more about JAVA at brainly.com/question/12978370

#SPJ1

3 0
2 years ago
A single-platter disk has rotation speed 7200 rpm, number of tracks on one side of platter is 30,000, number of sectors per trac
nexus9112 [7]

Answer:

Rotation Speed = 7200 rpm

No. of tracks on one side of platter = 30000

No. of sectors per track = 600

Seek time for every 100 track traversed = 1 ms

To find:

Average Seek Time.

Average Rotational Latency.

Transfer time for a sector. Total Average time to satisfy a request.

Explanation:

a) As given, the disk head starts at track O. At this point the seek time is 0.

Seek time is time to traverse from 0 to 29999 tracks (it makes 30000)

Average Seek Time is the time taken by the head

to move from one track to another/2

29999 / 2 = 14999.5 ms

As the seek time is one ms for every hundred

tracks traversed. So the seek time for 29,999 tracks traversed is

14999.5/100 = 149.995 ms

b) The rotations per minute are 7200

1 min = 60 sec

7200 / 60 = 120 rotations / sec

Rotational delay is the inverses of this. So 1/120 = 0.00833 sec

= 0.00833 * 100

= 0.833 ms

So there is 1 rotation is at every 0.833 ms

Average Rotational latency is one half the amount of time taken by disk to make one revolution or complete 1 rotation.

So average rotational latency is: 1 / 2r

8.333/2 = 4.165 ms

c) No. of sectors per track = 600

Time for one disk rotation = 0.833 ms

So transfer time for a sector is: one disk revolution time / number of sectors

8.333 / 600 = 0.01388 ms = 13.88 μs

d) Total average time to satisfy a request is calculated as :

Average seek time + Average rotational latency + Transfer time for a sector

= 149.99 ms + 4.165 ms + 0.01388 ms

= 154.168 ms

4 0
2 years ago
Susan wants to communicate with Julia. Arrange the steps of the communication process in the correct order.
yKpoI14uk [10]
1. Encoding
2. Medium of transmission
3. Decoding
4. Feedback
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3 years ago
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aleksley [76]

Answer:

Explanation:

1.first select the cells that you written and then click on the auto sum feature in ms excel and you values are added in ms excel

hope it helps you

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2 years ago
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Is 920 a good score on the psat?
enyata [817]
It all depends on your grade level. For sophomores, I would assume that it is an average score ( I am a sophomore myself, but I received a 1270). For juniors, this is below average. Your schools curriculum comes into play as well. So in short, yes or sophomores and no for juniors.
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