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vivado [14]
2 years ago
15

Four bricks of length l, identical and uniform, are stacked on top of one another (the figure) in such a way that part of each e

xtends beyond the one beneath. Find, in terms of l, the maximum values of (a) a1, (b) a2, (c) a3, (d) a4, and (e) h, such that the stack is in equilibrium
SAT
1 answer:
xeze [42]2 years ago
6 0

The maximum values of a₁, a₂, a₃, a₄ and h to make the stack in equilibrium are; a₁_max = L/2; a₂_max = L/4; a₃_max = - L/6; a₄_max = -L/8; h = 25L/24

<h3>What is the maximum width?</h3>

The system is in equilibrium and length of each brick = L

a) For brick 1;

Due to the fact that the center of gravity lies to the right of L/2,

Then we can say that the maximum value of a₁ = L/2

b) For brick 2;

Since the center of gravity lies to the right of L/2, then we can say that;

The maximum value of a₂ = ¹/₂a₁_max

Thus, the maximum value of a₂ = L/4

c) For brick 3;

Taking the moment of force, the maximum value of a₃ is;

a₃_max =  [(-¹/₂mL) + 2m(0)]/(2m +m)

a₃_max = - L/6

d) For the brick 4;

Taking the moment of force, the maximum value of a₄ is;

a₄ = [3(0) m + m(-L/2)]/(3m + m)

a₄_max = -L/8

e) The value of h = |a1| + |a2| +|a3| + |a4|

h = L/2 + L/4 + L/6 + L/8

h = ((12 + 6 + 4 + 3)/24)L

h = 25L/24

Read more about center of mass at; brainly.com/question/16835885

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A sample of pure lithium nitrate contains 7. 99% lithium by mass. What is the % lithium by mass in a sample of pure lithium nitr
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Considering the definition of percentage by mass, the sample of pure lithium nitrate contains 7.99% lithium by mass.

<h3>Definition of percentage by mass</h3>

The percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.

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The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:

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<h3>This case</h3>

Because percent by mass indicates the ratio of solute to solution based on mass, if the sample has twice the mass of the first sample, the ratio remains constant.

So the percentage by mass is the same.

That is, the sample of pure lithium nitrate contains 7.99% lithium by mass.

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