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mylen [45]
2 years ago
7

Identify the meaning of the variables in the point-slope form of a line.

Mathematics
1 answer:
user100 [1]2 years ago
6 0

In the point-slope form of a line, (y-y1)=m(x-x1)

'm' represents the slope of the line.

(x1,y1) represents a given point on the line.

(x,y) represents any point on the line.

The equation of a straight line that passes through a particular point and is inclined at a specific angle to the x-axis can be found using the point slope form.

A straight line is represented using its slope and a point on the line using point slope form. This means that the point slope form is used to determine the equation of a line whose slope is "m" and passes through the point (x1,y1).

The point slope form's equation is (y-y1)=m(x-x1), where (x, y) is a randomly chosen point on the line and m is the slope.

Learn more about point-slope form here:

brainly.com/question/6497976

#SPJ1

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The combined average weight of an okapi and llama is 450 kg average weight of three llamas is 190 more than average weight of an
Vladimir79 [104]

Answer:

The average weight of okapi  is 290 kg

The average weight of llama is 160 kg

Step-by-step explanation:

To solve the question, we are to resolve the word problem as follows;

Let the average weight of Okapi be X

The average weight of llamas be Y

X + Y = 450 and

3 Y = X + 190

Solving the above simultaneous equation, we have

X = 450 - Y

∴ 3·Y = 450-Y+190

4·Y =640

Y = 160 and X = 450 - 160 = 290

Therefore, the average weight of okapi  = 290 kg while the average weight of llama = 160 kg.

5 0
3 years ago
Find the slope and y intercept of 2y +8 = 6x + 4
cricket20 [7]
Slope (3) y intercept (0,-2)
8 0
3 years ago
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Point P is located -13, and point Q is located at 8.
marshall27 [118]
2

Hope this helps

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5 0
2 years ago
A scientist has 100 milligrams of a radioactive element. The amount of radioactive element remaining after t days can be determi
grandymaker [24]
The mass of the first shipment at time t is
m_{1}=100( \frac{1}{2} )^{ \frac{t}{10}}

The mass of the second shipment at time t is
m_{2}=100( \frac{1}{2} )^{ \frac{t-3}{10} }

At time t, the ratio of m₁ to m₂ is
\frac{m_{1}}{m_{2}} = \frac{100}{100}. \frac{(1/2)^{t/10}}{(1/2)^{(t-3)/10}} \\ =  \frac{(1/2)^{t/10}}{(1/2)^{t/10}}. \frac{1}{(1/2)^{-3/10}} \\ = (1/2)^{3/10} \\ = 0.8123

Therefore as a percentage,
\frac{m_{1}}{m_{2}} =100*0.8123 = 81.23 \%

Answer: B. 81.2%

4 0
3 years ago
HELP PLEASE <br> What is the area of the kite below?
Kryger [21]

Answer:

Area = 33 inches squared

Step-by-step explanation:

The formula for the area of a kite is:

Area = ½ × (d)1 × (d)2

To find the first diagonal (d1):

d1 = 7 in + 4 in = 11 in

To find the second diagonal (d2):

The triangles on the right of the kite must be 3 4 5 triangle since it is a right triangle with a hypotenuse of 5 and a side of 4, we know half of a diagonal would be 3 inches.

d2 = 3 in + 3 in = 6 in

Now we can plug the diagonals into the area formula.

Area = ½ × 11 × 6 = 33 inches squared

6 0
2 years ago
Read 2 more answers
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