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xenn [34]
3 years ago
8

Mr. Jenson is planning a painting project. He has purchased paint and supplies for $650. He will also hire a painter for

Mathematics
1 answer:
Sever21 [200]3 years ago
3 0

Answer:

The last Table

Step-by-step explanation:

After 2 hours of work, you will be charged $80. Add this to the already charged $650 and you will have $730. For each hour add an additional $40 to that cost. The last table matches this.

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Area of triangle height 10 feet<br> Base 4x squared + 2xy squared feet
Brums [2.3K]

Answer:

Since the formula is (1/2) base height, (1/2) of 10 is 5 so multiply 5 times the base polynomial resulting in 20x^2y + 10xy^2 ft^2. So, if you multiply the length times width then divide by 2 you get the same answer. Sorry if this is incorrect.

Hope this helps, have a great day and stay safe!

6 0
3 years ago
Solve the equation using elimination<br> 3x+8x=-5<br> -2x+2y=18
Nina [5.8K]
X= -7 y=2 (-7,2).

You multiply the first equation by 2 and the second by 3, then you can cancel out the x values to get the y value. Then you go back and plug in the y value to get x.
7 0
3 years ago
How do I solve this problem?
umka2103 [35]

Answer:

theta = all real values

Step-by-step explanation:

sec theta + tan theta  = cos theta / (1-sin theta )

sec theta = 1/cos theta

tan theta = sin theta/cos theta

1/cos theta + sin theta /cos theta= cos theta/ (1-sin theta)

(1+ sin theta) / cos theta = cos theta /( 1-sin theta)

using cross products

(1+sin theta) * (1-sin theta) = cos theta * cos theta

1 +sin theta - sin theta- sin^2 theta= cos ^2 theta

1 - sin ^2 theta= cos ^2 theta

cos ^2  theta= cos ^2 theta

this is an identity so it is true for all theta

7 0
3 years ago
Plz help.......................
True [87]
Let's use the slope intercept form of a line which is:

y=mx+b where m=slope and b=y-intercept.

Mathematically m=(y2-y1)/(x2-x1) and the y-intercept is just the value of y when x is equal to zero, where the line intercepts the y axis...

First you want to find the slope by finding two clearly identifiable points on the graph...I'll pick (4,4) and (0,1), now we can calculate the slope or "m"...

m=(4-1)/(4-0)=3/4 so now we can say our line is:

y=0.75x+b, using point (4,4) we can now solve for b.

4=0.75(4)+b

4=3+b

b=1 so the line is"

y=0.75x+1
4 0
4 years ago
PLEASE ANSWER ASAP!!!!
Arlecino [84]

We'll use the notation \textrm{Arcsin } x for the principal value and \arcsin x for all the values:


\arcsin x = \textrm{Arcsin } x + 2\pi k \textrm{ or } (\pi - \textrm{Arcsin }x) + 2\pi k \quad \textrm{ integer } k


Part I


\sin(\theta/2) = \frac 1 2


\theta/2 = \arcsin \frac 1 2


Part II. In our range we can write


\sin(\theta/2) = \sin(\frac \pi 6)


\theta/2 = \frac \pi 6 \textrm{   or   } \theta /2 = \pi - \frac \pi 6 = \frac{5\pi}{6}


Part III.


\theta = \frac \pi 3 \textrm{   or   } \theta = \frac{5\pi}{3}


Part IV.


\theta/2 = \frac \pi 6 + 2\pi k \textrm{ or } \theta = \frac{5 \pi}{6} + 2\pi k \quad \textrm{integer } k

\theta = \frac \pi 3 + 4 \pi k \textrm{   or   } \theta = \frac{5 \pi}{3} + 4\pi k  \quad \textrm{integer } k



5 0
3 years ago
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