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KonstantinChe [14]
2 years ago
11

Which general staff member directs all responses and tactical actions to achieve the incident?.

Business
1 answer:
ch4aika [34]2 years ago
4 0

The Operations Section Chief directs all responses and tactical actions to achieve the incident objectives.

<h3>What is Operations Section Chief ?</h3>

The Operations Section Chief, a member of the General Staff, is in charge of all operations directly related to the core mission. The Operations Section Chief initiates, supervises, and leads the execution of organizational elements in accordance with the Incident Action Plan.

The Operations Section Chief directs tactical incident activities to achieve incident objectives and oversees the implementation of the Incident Action Plan (IAP). 1. This role can be ordered as a stand-alone resource or as part of a National Incident Management System (NIMS) team (Incident Management Team).

The OSC1 works in the Operations functional area and reports to the Incident Commander (IC). The OSC1 performs duties corresponding with the Type 1 incident complexity and characteristics outlined in the Interagency Standards for Fire and Firefighting.

To know more about Operations Section Chief  follow the link:

brainly.com/question/25870256

#SPJ4

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Assume that we are back to talking about bags of oranges (a private good), but that the government has decided that tossed orang
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Answer:

If negative externalities pop up in a market, the equilibrium is higher than the efficient output.

Thus when it comes to the government rectification regarding the side effects of that commercial , activity, if the amount of bags is (1) then the new equilibrium would be: <em>p*= $17</em>

8 0
3 years ago
Why can internet banks offer better interest rates and lower fees than tradition banks?
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C I think bro Ishtar
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3 years ago
Using the interest formula, compute the interest and maturity values for each of the following notes: Principal Interest Term Ra
Ad libitum [116K]

Answer:

The answer is:

A: I=$76,67    MV=$4076,67

B: I=$293,75  MV=$10293,75

C: I=$138,125 MV=$6638,125

D: I=$36,75    MV=$936,75

Explanation:

Notes are often a key component of how a business finances its operations. For purposes of accounting, it's important to be able to calculate the maturity value of a note to know how much a business will have to pay or receive when the note comes due.

In general, notes are a form of short-term commercial financing. The maturity value is the amount of money that the company would receive when the note comes due.

When you know the principal amount, the rate, and the time, the amount of interest can be calculated by using the formula:

I = P*r*t

I= Total interest

P= principal

r= interest rate

t= time

To calculate the Maturity Value you need to sum the principal to the total interest accumulated over time.

Maturity Value= Principal + Interest

<u>In this exercise:</u>

<u>A:</u>

Principal: $4000    r=11,5%       t=60 days

I=4000*0,115*(60/360)= $76,67

Maturity Value= 4000 + 76,67= $4076,67

<u>B:</u>

Principal: $10,000          r=11.75%        t=90 days

I=10000*0,1175*(90/360)= $293,75

Maturity Value= 10000+ 293,75= $10293,75

<u>C:</u>

Principal= $6,500   r=12.75%          time=60 days

I=6500*0,1275*(60/360)= $138,125

Maturity Value= 6500+ 138,125= $6638,125

<u>D:</u>

Principal= $900     r= 12.25%     time=120 days

I=900*0,1225*(120/360)= $36,75

Maturity Value= 900+ 36,75= $936,75

4 0
3 years ago
. A manufacturer uses manages its inventory using fixed quantity system and wants to be able to fully supply its customers at le
Vsevolod [243]

Answer:

Lead time needed is approximately 1 day

Explanation:

In this question, we are asked to calculate the maximum number of lead days needed by a manufacturer to give a supplier

We proceed as follows;

They want to be able to fully supply the customer at least 50 out of the 52 weeks.

Mathematically; service probability = 50/52 = 0.96 or 96%

At 96% service level value of Z = 1.75

Standard deviation of daily demand (σd) = 50 units

Safety stock = 100 units

Suppose lead time = L

Safety stock = Z × σ d × √L

100 = 1.75 × 50 × √L

=100 = 87.5 × √L

√L = 100/87.5

√L = 1.142857142

L = 1.142857142^2

L = 1.306122448

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4 years ago
A company estimates that 0.7% of their products will fail after the original warranty period, but within two years of the purcha
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Answer:

The company's expected value of each warranty sold = $45.55

Explanation:

x = Resulting value for the company of replacing a failed product = Price two-year-extended warranty - Replacement cost = $48 - $350 = -$302

y = Resulting value for selling extended warranty to a product that does not fail = Price two-year-extended warranty = $48

Px = Probability of X occurring = 0.7%

Py = Probability of y occurring = 100% - Px = 100% - 0.7% = 99.30%

Therefore, we have:

The company's expected value of each warranty sold = (x * Px) + (y * Py) = ((-$302) * 0.7%) + ($48 * 99.30%) = $45.55

8 0
3 years ago
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