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2 years ago

Help ASAP math studyisland

Mathematics

1 answer:

kifflom [539]2 years ago

8 0

A function relates an input to an output.

<span>It is like a machine that has an input and an output.And the output is related somehow to the input.so an example of a funtion is f(X) </span>

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Alex777 [14]

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2 years ago

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Andrews [41]

Answer:

Answer: 1 1/4

Step-by-step explanation:

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Find the slope of the given points (3,4) and (7,-4)

mr Goodwill [35]

Answer:

Step-by-step explanation:

$\bold{slope\, (m)=\dfrac{change\ in\ Y}{change\ in\ X}=\dfrac{y_2-y_1}{x_2-x_1}}$

(3, 4) ⇒ x₁ = 3, y₁ = 4

(7, -4) ⇒ x₂ = 7, y₂ = -4

So the slope:

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3 years ago

Find the domain and range of the relation and determine whether it is a function.

AnnZ [28]

The domain is all of the x - values, while the range is all of the y - values. If there are two point with the same x - values, then it is not a function. Therefore, your answer would be A.
Hope this helped, and have a nice day!

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3 years ago

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<img src="https://tex.z-dn.net/?f=2h-3%5C%20%20%5Ctextgreater%20%5C%2015" id="TexFormula1" title="2h-3\ \textgreater \ 15" alt=

skelet666 [1.2K]

$\huge\text{Hey there!}$

$\large\textsf{2h - 3 }\mathsf{>}\large\textsf{ 15}$

$\large\text{ADD 3 to BOTH SIDES}$

$\large\textsf{2h - 3 + 3 }>\large\textsf{ 15 + 3}$

$\large\text{CANCEL out: \textsf{-3 + 3} because that gives you 0}$

$\large\text{KEEP: \textsf{15 + 3} because it helps you solve for your h-value}$

$\large\textsf{15 + 3 = \boxed{\large\textsf{\bf 18}}}$

$\large\text{NEW EQUATION: \textsf{2h} }\mathsf{>}\large\textsf{ 18}$

$\large\text{DIVIDE 2 to BOTH SIDES}$

$\mathsf{\dfrac{2h}{2}>\dfrac{18}{2}}$

$\large\text{CANCEL out: }\mathsf{\dfrac{2}{2}}\large\text{ because it gives you 1}$

$\large\text{KEEP: }\mathsf{\dfrac{18}{2}}\large\text{ because it gives you your h-value is being compared to}$

$\large\text{NEW EQUATION: }\mathsf{h > \dfrac{18}{2}}$

$\mathsf{\dfrac{18}{2}}$

$\mathsf{= 18\div 2}$

$=\boxed{\mathsf{\large\textsf {\bf 9}}}$

$\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf h > 9}}}\huge\checkmark\\\\\boxed{\boxed{\rm \bf It\ it\ an\ O P E N E D\ circle\ shaded}}\\\boxed{\boxed{\rm \bf to\ the\ right\ starting\ at\ point\ 9}}\checkmark$

$\large\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

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2 years ago

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