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DiKsa [7]
3 years ago
8

Please help I'm so confused and I really need to get this done

Mathematics
1 answer:
Fudgin [204]3 years ago
4 0
A) Five-number summary:

1. sample minimum
2. first quartile
3. median
4. third quartile
5. maximum

0) Order the data

State A: 4, 5, 6, 6, 7, 8, 9, 21, 25

State B: 10, 11, 12, 13, 14, 14, 15, 15, 16


 1) Minimum:

State A: 4
State B: 10

2) Median: the middle of the sample

State A: 7
State B: 14

3) first quartle : the median of the first half:

State A: (5+6)/2 = 5.5
State B: (11+12)/2 = 11.5

4) third quartile: the median of the higher half

State A: (9+21) /2 = 15
State B: 15

5) Sample maximum:

State A: 25
State B: 16

6) Interquartile range: 3rd quartile - 1st quartile

State A: 15 - 5.5 = 9.5
State B: 15 -  11.5  = 4.5
 

B) Symmetry:

Distance to the median and the quartiles:

State A:

median - first quartile: 7 - 5.5 = 1.5

third quartile - median: 15 - 7 = 8

1.5 ≠ 8 => skewed (not symmetrical)

State B

median - first quartle : 14 - 11.5 = 2.5

third quartile - median: 15 -14 = 1

2.5 ≠ 1 => skewed  
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A data set lists weights​ (lb) of plastic discarded by households. The highest weight is 5.31 ​lb, the mean of all of the weight
a_sh-v [17]

Answer:

a) The difference is of 3.222 lbs.

b) 1.64 standard deviations.

c) Z = 1.64

d) Not significant, as the z-score of 1.64 is between -2 and 2.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The mean of all of the weights is x=2.088 ​lb, and the standard deviation of the weights is s=1.968 lb.

This means that \mu = 2.088, \sigma = 1.968

a. What is the difference between the weight of 5.31 lb and the mean of the​ weights?

This is X - \mu = 5.31 - 2.088 = 3.222

The difference is of 3.222 lbs.

b. How many standard deviations is that​ [the difference found in part​ (a)]?

This is the z-score. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.31 - 2.088}{1.968}

Z = 1.64

1.64 standard deviations.

c. Convert the weight of 5.31 lb to a z score.

Z = 1.64, as found above.

d. If we consider weights that convert to z scores between −2 and 2 to be neither significantly low nor significantly​ high, is the weight of 5.31 lb​ significant?

Not significant, as the z-score of 1.64 is between -2 and 2.

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