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DiKsa [7]
3 years ago
8

Please help I'm so confused and I really need to get this done

Mathematics
1 answer:
Fudgin [204]3 years ago
4 0
A) Five-number summary:

1. sample minimum
2. first quartile
3. median
4. third quartile
5. maximum

0) Order the data

State A: 4, 5, 6, 6, 7, 8, 9, 21, 25

State B: 10, 11, 12, 13, 14, 14, 15, 15, 16


 1) Minimum:

State A: 4
State B: 10

2) Median: the middle of the sample

State A: 7
State B: 14

3) first quartle : the median of the first half:

State A: (5+6)/2 = 5.5
State B: (11+12)/2 = 11.5

4) third quartile: the median of the higher half

State A: (9+21) /2 = 15
State B: 15

5) Sample maximum:

State A: 25
State B: 16

6) Interquartile range: 3rd quartile - 1st quartile

State A: 15 - 5.5 = 9.5
State B: 15 -  11.5  = 4.5
 

B) Symmetry:

Distance to the median and the quartiles:

State A:

median - first quartile: 7 - 5.5 = 1.5

third quartile - median: 15 - 7 = 8

1.5 ≠ 8 => skewed (not symmetrical)

State B

median - first quartle : 14 - 11.5 = 2.5

third quartile - median: 15 -14 = 1

2.5 ≠ 1 => skewed  
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Stock worth $80 a share dropped in value by 15% on Tuesday, then increased by $7 the next Wednesday and, finally, increased by 1
Nutka1998 [239]
<h2>Steps</h2>

So here are a couple expressions when a value changes by percentage (p = percentage in decimal form and m = original value):

  • When <em>decrease</em>: (1 - p)m
  • When <em>increase</em>: (1 + p)m

So firstly, the $80 share dropped by 15%. Since this is a <em>decrease</em>, follow the appropriate expression:

15\%=0.15\\\\(1-0.15)*80\\0.85*80\\68

<em>On Tuesday, the share went from $80 to $68</em>

Next, on Wednesday the share increased by $7. With this, just add $68 and 7.

68+7=75

<em>On Wednesday, the share went from $68 to $75</em>

Lastly, on Thursday the share increased by 12%. Since this is an <em>increase</em>, follow the appropriate expression:

12\%=0.12\\\\(1+0.12)*75\\1.12*75\\84

<h2>Answer</h2>

<u>The final price of the share is $84.</u>

7 0
3 years ago
Can someone help me with this, im not really good at math and i dont understand this :(​
cluponka [151]

Answer:

y = 2x + 4

Step-by-step explanation:

First find 2 points on the line to determine slope.

(0, 4) and (2, 8)

Slope = \frac{8-4}{2-0}=2

y = 2x + b

b = y - intercept

b = 4

y = 2x + 4

4 0
3 years ago
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Solve using substitution.<br><br> y = –1<br> 2x − y = –1
irakobra [83]
X =1 I had this question
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I don't understand proportional relationship can u help? ​
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Answer: I’ll explain it in simpler terms for you. A proportional relationship is one in which two quantities vary directly with each other. Ratios are proportional if they represent the same relationship. One way to see if two ratios are proportional is to write them as fractions and then reduce them. If the reduced fractions are the same, your ratios are proportional. An example of a proportional relationship is simple interest, tax, markups and markdowns, gratuities and commissions, fees, percent increase and decrease, percent error. Hope this helps! :D

5 0
2 years ago
17. Admission prices to Cinema I to see a movie are $9.50 for an adult and $6.50 for a child. The admission charge at Cinema II
maksim [4K]

Answer:

a. 9.5x + 6.5(x+c) < 8   when c>0

b. Must be one child more than the no. of adults.

Step-by-step explanation:

For Cinema 1:

for adult = $9.50

for child = $6.50

For Cinema 2:

Per person regardless of age = $8.00

First of all, we will find out the condition when per person rates in both cinema are equal.

Assume x = no. of adults

y = no. of children

Rate per person in Cinema I = Rate per person in Cinema II

(9.5x + 6.5y)/(x+y)   =   8

9.5x + 6.5y = 8(x+y)

9.5x + 6.5y = 8x + 8y

9.5x-8x = 8y-6.5y

=> x = y

So rates are equal when no. of adults equals no. of children

For Cinema I to have better rates, no. of children should be atleast 1 more than the no. of adult. In this way the rate per person of Cinema I will be less than 8

Hence we form an inequality when y = x+c and c > 0

9.5x + 6.5(x+c) < 8   when c>0

Hence there must be 1 more children than the no. of adults attending Cinema I for it to be a better deal.

4 0
3 years ago
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