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BlackZzzverrR [31]
2 years ago
6

For a standard normal​ curve, find the​ z-score that separates the bottom​ 70% from the top​ 30%.

Mathematics
1 answer:
Fiesta28 [93]2 years ago
4 0

Using the normal distribution, the z-score that separates the bottom​ 70% from the top​ 30% is z = 0.525.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The z-score that separates the bottom​ 70% from the top​ 30% is <u>z with a p-value of 0.7</u>, hence z = 0.525.

More can be learned about the normal distribution at brainly.com/question/24537145

#SPJ1

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