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Colt1911 [192]
2 years ago
8

Explain why the surface area of a right prism can be found using the formula

Mathematics
1 answer:
kipiarov [429]2 years ago
5 0

Answer:

ph : perimeter = 4 sides of the base; p*h = the area of the sides of that prism

B : 2 areas of the base = top and bottom

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A postal carrier can
ioda

Answer: 6 hours or 360 minutes

Step-by-step explanation:

First find out how long it takes to deliver to one house.

Convert hours to minutes.

2.5 x 60 = 150 minutes total

Divide to find the time per house

150 minutes / 130 houses = 1.15 minutes per house

Now multiply this rate by the number of houses (312).

312 x 1.15 = 360 minutes

If you want it in hours then divide by 60.

360/60 = 6 hours.

6 0
3 years ago
Are these correct???
velikii [3]

Answer:

yes

Step-by-step explanation:

8 0
3 years ago
Select the postulate that is illustrated for the real numbers.
Alex Ar [27]
I think the correct answer from the choices listed above is the distributive postulate. The expression 3x + 3 = 3(x + 1) is an example of a distributive postulate. It <span>says that multiplying a number by a group of numbers added together is the same as doing each multiplication separately.  Hope this answers the question.</span>
5 0
3 years ago
Read 2 more answers
Please solve this for me​
Artist 52 [7]
Ax^2 + bx + c = 0
x^2 - 5x = 14
x^2 - 5x - 14 = 0
a = 1
b = -5
c = -14
3 0
3 years ago
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Can a quadratic polynomial equation with real coefficients have one real solution and one complex solution? If so,
Anastasy [175]

Answer:

No

Step-by-step explanation:

We have to find that a quadratic polynomial equation with real coefficient can have one real solution and one complex solution.

quadratic equation is given by

ax^2+bx+c=0

It can be written as  the product of linear factors

ax^2+bx+c=a(x-r_1)(x-r_2)

Where r_1,r_2 are solutions of the given  polynomial equation.

No , a quadratic polynomial equation can not  have one real solution and one complex solution because complex root are always in paired not a single.

A quadratic equation have two roots only.

If a quadratic equation have complex root then the equation have both complex root .

If  a equation have real root then it have both real.

Therefore, a quadratic equation can not have one real and one compelx solution.

5 0
3 years ago
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