The complete question is shown in the figure below. As you can see one square units is well shown in the graph. So we can conclude that the distance between two consecutive points is 1 unit. If so, then we can calculate the area of the parallelogram as follows:
Then, finding CB by Pythagorean Theorem:
And:
Therefore:
ANSWER
The domain of the function is
or
[-3,6]
EXPLANATION
The domain of a function refers to the values of x for which the function is defined.
From the graph, we can see that the function begins at (-3,6) and ends at (6,-4).
Therefore the function is defined for x=-3 to x=6.
Hence the domain of the function is
or
[-3,6]
The amount of water in the pool after t minutes is modeled by the linear function , hence it is a function of time.
A <em>linear function</em> for the amount of water in the pool, considering that it is <u>drained at a rate of a gallons per minute</u>, is modeled by:
In this problem, draining her hot tub at a rate of <u>5.5 gallons per minute</u>, hence , and:
Which is a function of time.
To learn more about linear functions, you can take a look at brainly.com/question/13488309
Answer:
1) the planning value for the population standard deviation is 10,000
2)
a) Margin of error E = 500, n = 1536.64 ≈ 1537
b) Margin of error E = 200, n = 9604
c) Margin of error E = 100, n = 38416
3)
As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.
Hence, I will not recommend trying to obtain the $100 margin of error in the present case.
Step-by-step explanation:
Given the data in the question;
1) Planning Value for the population standard deviation will be;
⇒ ( 50,000 - 10,000 ) / 4
= 40,000 / 4
σ = 10,000
Hence, the planning value for the population standard deviation is 10,000
2) how large a sample should be taken if the desired margin of error is;
we know that, n = [ ( × σ ) / E ]²
given that confidence level = 95%, so = 1.96
Now,
a) Margin of error E = 500
n = [ ( × σ ) / E ]²
n = [ ( 1.96 × 10000 ) / 500 ]²
n = [ 19600 / 500 ]²
n = 1536.64 ≈ 1537
b) Margin of error E = 200
n = [ ( × σ ) / E ]²
n = [ ( 1.96 × 10000 ) / 200 ]²
n = [ 19600 / 200 ]²
n = 9604
c) Margin of error E = 100
n = [ ( × σ ) / E ]²
n = [ ( 1.96 × 10000 ) / 100 ]²
n = [ 19600 / 100 ]²
n = 38416
3) Would you recommend trying to obtain the $100 margin of error?
As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.
Hence, I will not recommend trying to obtain the $100 margin of error in the present case.