Answer:
below
Step-by-step explanation:
I'm pretty sure this is the answer.
Answer:
A. 3.0 m/s
Step-by-step explanation:
Based on the graph,
velocity = Area of the graph
(y : position and x : time)
Let y1 = 2m and y2 = 14m,
t1 = 0s and t2 = 4s
v = (14 - 2)m/(4-0)s
= 12m/4s
= 3.0 m/s
Answer:
4.91
Step-by-step explanation:
4¹/6*2¹/5
25/6*11/5
275/30
4.91
5
Answer: 57 ft
Step-by-step explanation: Because drawing it up, we can make a right angled triangle with the right angle between the height of the man in the building and the distance out from the building of the man in the street, and the 35 degrees between the line connecting the man in the street with the man in the building, and the line out from the building of the man in the street. Then, tan of the 35 degree angle is = to opposite (40ft)/adjacent (to solve for). By cross multiplication, the A or adjacent (dist out from the building) = 40/0.7 (0.7 = tan of 35 degrees) so the answer is 57 ft.
Answer:
- <u><em>The solution to f(x) = s(x) is x = 2012. </em></u>
Explanation:
<u>Rewrite the table and the choices for better understanding:</u>
<em>Enrollment at a Technical School </em>
Year (x) First Year f(x) Second Year s(x)
2009 785 756
2010 740 785
2011 690 710
2012 732 732
2013 781 755
Which of the following statements is true based on the data in the table?
- The solution to f(x) = s(x) is x = 2012.
- The solution to f(x) = s(x) is x = 732.
- The solution to f(x) = s(x) is x = 2011.
- The solution to f(x) = s(x) is x = 710.
<h2>Solution</h2>
The question requires to find which of the options represents the solution to f(x) = s(x).
That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.
The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012,<em> x = 2012. </em>
Thus, the correct choice is the third one:
- The solution to f(x) = s(x) is x = 2012.
