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Alexxandr [17]
3 years ago
8

What is the largest number of pancakes that Benjamin can afford

Mathematics
1 answer:
aleksklad [387]3 years ago
3 0

Answer:

See explanation

Step-by-step explanation:

Here is the complete question:

Benjamin decides to treat himself to breakfast at his favorite restaurant. He orders chocolate milk that costs $3.25. Then, he wants to buy as many pancakes as he can, but he wants his bill to be at most $30 before tax. The restaurant only sells pancakes in stacks of 4 pancakes for $5.50 . Let S represent the number of stacks of pancakes that Benjamin buys. What is the largest number of pancakes that Benjamin can afford?

Given:

Cost of chocolate milk = $3.25

Maximum bill that Benjamin wants before tax = $30

Cost of stack of 4 pancakes = $5.50

Let S be the number of stacks of pancakes that Benjamin buys

Solution:

Cost per stack of pancakes = $5.50  

Cost of S number of stacks of pancakes = S*5.50  = 5.50 S

So benjamin will spend money on 1 chocolate milk and S number of stacks of pancakes

Compute the total money spent by Benjamin:

Cost of chocolate milk + cost per stack of pancakes = 3.25 + 5.50 S

Maximum bill that Benjamin wants is $30 So,

The total money should be less than equal to the maximum bill that benjamin wants i.e. less than or equal to 30. So it is represented as:

3.25 + 5.50S ≤ 30  ----- (1)

Now using (1) we can find the largest number of pancakes that  Benjamin can afford :

3.25 + 5.50S ≤ 30

5.50S ≤ 30 - 3.25    

subtract 3.25 from 30

5.50S ≤ 26.75

Divide by 5.50

S ≤ 4.863636

S ≤ 4.86

S≤ 4 approx

Since the restaurant only sells pancakes in stacks of 4 pancakes so,

4 stacks = 4 *4 =  16

So the largest number of pancakes that Benjamin can afford are 16.

If we do not round off the the value stacks then we get:

4.86 stacks = 4.86 *4 =  19.44 pancakes

So the largest number of pancakes that Benjamin can afford are 19

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Answer:

x = 6

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
-3/v=-6 simply as much as possible
Aleksandr [31]
Hey!


In order to simplify this equation, we'll first have to multiply both sides of the equation by v. This will give us v on its own.

<em>Original Equation :</em>
\frac{-3}{v} = -6

<em>New Equation {Added Multiply Both Sides by V} :</em>
\frac{-3}{v} v=-6v

<em>Solution {New Equation Solved} :</em>
-3 = -6v

Now we'll switch sides to get v on the left side of the equation which is generally where we always want the variables to be located in these types of equations.

<em>Old Equation :</em>
-3 = -6v

<em>New Equation {Switched} :</em>
-6v=-3

Now we'll divide both sides by v to get v on its own.

<em>Old Equation :</em>
-6v = -3

<em>New Equation {Added Divide Both Sides by V} :</em>
\frac{-6v}{v} = \frac{-3}{v}

<em>Solution {New Equation Solved} :</em>
v =  \frac{1}{2}

<em>So, this means that in the equation \frac{-3}{v} =-6,</em>  v =  \frac{1}{2}.

Hope this helps!


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Answer:

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Step-by-step explanation:

4x-3y=8

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Is there any of the like terms can be added and the result will be 0? No, so we have to multiple one OR both of the equations to make that one number do that.

(I will try to remove the y like terms so i will multiple both of them by the opposite so both of the ys will be 6)

2(4x-3y=8)

-3(5x-2y=-11)

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(now the easy part… cancel the 6s and add the equations)

8x+(-15x)=-7x

16+33=49

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(divide 49 by -7)

x=-7

Replace x in any of the equations and you’ll get the y value.

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Answer:

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