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1 year ago

11

Factorise :ab(x^2 - y^2) + (a^2 - b^2)xy = 0

1 answer:

yawa3891 [41]1 year ago

7 0

Step-by-step explanation:

abx^2-aby^2+xya^2-xyb^2

abx^2+xya^2-aby^2-xyb^2

ax(bx+ya)-yb(ay+xb)

ax(bx+ya)-yb(xb+ay)

(ax-yb) (bx+ya)

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Describe and correct any error a student may have made when solving the equation

Lady_Fox [76]

Answer:

The student made an error during the distributive property in the second step where they multiplied 0.15 by -0.2 to equal -0.3 when it should have been -0.03.

Step-by-step explanation:

$0.15(y-0.2)=2-0.5(1-y)\\0.15y-0.03=2-0.5+0.5y\\0.15y-0.03=1.5+0.5y\\100(0.15y-0.03)=100(1.5+0.5y)\\15y-3=150+50y\\15y-3-15y-150=150+50y-15y-150\\-153=35y\\-\frac{153}{35}=y$

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2 years ago

Am I dealing with harmonic stuff (trig)?

pochemuha

You just need to solve for when $y=0$ :

$\dfrac{\cos8t-9\sin8t}4=0\implies\cos8t-9\sin8t=0$

$\implies\cos8t=9\sin8t$

$\implies\dfrac19=\dfrac{\sin8t}{\cos8t}=\tan8t$

$\implies8t=\tan^{-1}\dfrac19+n\pi$

$\implies t=\dfrac18\tan^{-1}\dfrac19+\dfrac{n\pi}8$

where $n$ is any integer. We only care about when $0\le t\le1$ , which happens for $n\in\{0,1,2\}$ .

$t=\dfrac18\tan^{-1}\dfrac19\approx0.01$

$t=\dfrac18\tan^{-1}\dfrac19+\dfrac\pi8\approx0.41$

$t=\dfrac18\tan^{-1}\dfrac19+\dfrac\pi4\approx0.80$

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3 years ago

Which equation describes Which equation describes a line perpendicular to line R that passes through the point (3, -6)?

kompoz [17]

Answer:

B

Step-by-step explanation:

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2 years ago

Eric kept track of his days is a journal:

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Answer:

3

Step-by-step explanation:

5 percent * 60 =

(5:100)* 60 =

(5* 60):100 =

300:100 = 3

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2 years ago

Read 2 more answers

Someone help please need it asapp

mojhsa [17]

The answer is f(-2)=g(-2

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3 years ago