Answer:
D
Step-by-step explanation:
Perfect square trinomials can be written as (a + b)² = a² + 2ab + b². In this case, we know that a = x so we can write this as x² + 2bx + b². Since we know that 2bx = 24x we can conclude that b = 12, so that means b² = 12 * 12 = 144.
Answer: The GREATEST number of bookmarks that Logan can make = 31.
Step-by-step explanation:
GIven: Total petals = 95
Number of petals required for each bookmark = 3
Number the number of bookmarks can be prepared from 95 petals = 95 ÷ (Petals required of each bookmark)
= 95÷3
![=31\dfrac{2}{3}\ \ \ \approx31\text{ [Round to the nearest whole number.]}](https://tex.z-dn.net/?f=%3D31%5Cdfrac%7B2%7D%7B3%7D%5C%20%5C%20%5C%20%5Capprox31%5Ctext%7B%20%20%20%20%5BRound%20to%20the%20nearest%20whole%20number.%5D%7D)
i.e. The GREATEST number of bookmarks that Logan can make = 31.
Step-by-step explanation:
Given - In selecting a sulfur concrete for roadway construction in regions that experience heavy frost, it is important that the chosen concrete has a low value of thermal conductivity in order to minimize subsequent damage due to changing temperatures. Suppose two types of concrete, a graded aggregate and a no-fines aggregate, are being considered for a certain road. The table below summarizes data on thermal conductivity from an experiment carried out to compare the two types of concrete.
Type ni xi si
Graded 42 0.486 0.187
No-fines 42 0.359 0.158
To find - a. Formulate the above in terms of a hypothesis testing problem.
b. Give the test statistic and its reference distribution (under the null hypothesis).
c. Report the p-value of the test statistic and use it to assess the evidence that this sample provides on the scientific question of difference in mean conductivity of the two materials at the 5% level of significance.
Proof -
a.)
Hypothesis testing problem :
H0 : There is significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.
H1 : There is no significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.
b)
Test statistic :




⇒Z(cal) = 3.3687
Z(tab) = 1.96
As Z (cal) > Z(tab)
So, we reject H0 at 5% Level of significance
p-value = 0.99962
Hence
There is significant difference in mean conductivity at the two materials.
Answer:
3-th picture
Step-by-step explanation:
i think 3-th picture)
Answer:
495 cm
Step-by-step explanation:
Remark
When you do the subtraction, whatever is left (the decimal part) is the length in cm when multiplied by 100.
Solution
Remaining rope = starting length - what was used.
Remaining rope = 6.15 - 1.2
Remaining rope = 4.95 meters
Answer
The remaining rope = 4.95 * 100 = 495 cm