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3 years ago

.A town fair charges $6 for general

Mathematics

1 answer:

Darya [45]3 years ago

3 0

Answer: $1.50r + $6

Step-by-step explanation:

1.50 times 7 is $10.5 without admission

1.50 times 10 is $15 without admission

(R for rides)

so $1.50r + $6 is the equation

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17 hcf is 35 so what is 37

In-s [12.5K]

The hcf is 1 because 37 is a prime number so the only factors are 37 and 1 but 37 doesn’t go into 17 so the answer is 1

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3 years ago

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May someone, please help me with this

Shkiper50 [21]

Answer:

b probably

Step-by-step explanation:

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3 years ago

Peter is saving to buy a camera. The camera costs $50. Peter has already saved $23.25. His plan is to save $4.50 every week to s

Virty [35]

Answer:

m ≥ 6

Here, m is the number of weeks Peter need to save money.

Step-by-step explanation:

The cost of the camera = $50

The amount of money already saved = $23.25

The money saved in 1 week = $4.50

Now, The TOTAL money LEFT to be saved = Total camera cost - Money already saved

= $50 - $23.25 = $26.75

So, there is $26.75 yet to be saved.

Let us assume it takes m weeks to save $26.75.

So, money saved in m weeks = m x ( Money saved in 1 week)

or, $26.75. = m x ( $4.50)

or, m = $26.75 /$4.50 = 5.94

or, m = 5.94 ≈ 6 weeks

So, the money saved in at least 6 weeks = $26.75.

Hence, it would take AT LEAST 6 weeks to save up enough amount to buy the camera which costs $50.

⇒ m ≥ 6

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3 years ago

Drag the tiles to the boxes to form correct pairs

Brums [2.3K]

Answer:

1) $sin^{-1}(\frac{1}{\sqrt{2} })=45$

2) $cos^{-1}(\frac{\sqrt{3} }{2})=30$

3) $tan^{-1}(\sqrt{3})=60$

4) $sin^{-1}(1)=90$

Step-by-step explanation:

1) Value of $sin^{-1}(\frac{\sqrt{2} }{2}) =sin^{-1}(\frac{1}{\sqrt{2} })$

since sin45° = 1/√2

Therefore $sin^{-1}(\frac{1}{\sqrt{2} })=45$

2).Value of $cos^{-1}(\frac{\sqrt{3} }{2})$

Since cos 30° = √3/2

Therefore $cos^{-1}(\frac{\sqrt{3} }{2})=30$

3). Value of $tan^{-1}(\frac{3}{\sqrt{3} }) = tan^{-1}(\sqrt{3})=60$

since tan 60° = √3

therefore $tan^{-1}(\sqrt{3})=60$

4). Value of $sin^{-1}(1)$

Since sin90°=1

Therefore $sin^{-1}(1)=90$

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3 years ago

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While John is traveling along a straight interstate highway, he notices that the mile marker reads 243 km. John travels until he

loris [4]

Answer:

The displacement is: - 80 i

Step-by-step explanation:

In order to answer the question, you have to apply the displacement formula, which is:

ΔX= Xf-Xi

Where ΔX is the displacement, Xf is the final position and Xi is the initial position. The formula represents the change in the position of an object from the origin.

Let the origin be in 0 km,with the x-axis positive to te right.

Notice that the displacement is a vector. The positions are:

Xf=163 km (i)

Xi= 243 km (i)

Because John starts in 243 km and finishes in 163 km.

Where i is the unit vector in the x direction.

Therefore:

ΔX= 163 i - 243 i

Solving:

ΔX= -80 i

Notice that for calculating the displacement you just need the initial and final position. It doesn't depend on the distance traveled.

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3 years ago