Answer:
ok 4 ways
Step-by-step explanation:
1.add 5+4=9
if not
2.4-5=-1
if not
3. 4x5=20
if still not then
4. 4/5=0.8
hope that helps
Answer:
In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).
Step-by-step explanation:
There is really no need to use any quadratics or roots.
( Consider the same problem on the plain number line first. )
How do you find the number between 2 and 5 which is twice as far from 2 as from 5?
You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get
4=2+23(5−2)
It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then
R=P+23(Q−P)
so in your case we get
R=(0,−1)+23(3,3)=(2,1)
Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)
Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get
s=a+b=2b+b=3b
⇔b=13s⇒a=23s
Here you go, buddy. The answers are all in the image below.
Answer:
the correct option is option c.
Step-by-step explanation:
We have the expression: (160*243)^1/5
First, we know that 160 = 5(2^5)
And, 243 = 3^5
Then we have: (160*243)^1/5 = [5(2^5)(3^5)]^1/5 = 6(5)^1/5
So the correct option is option c.
-3x-4= +12
X negative 3 and 4 then add +12 to it.