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dangina [55]
2 years ago
14

Your friend finds that the correlation between shoe size and iq is r = 1. 99. what should you say about these findings?

Mathematics
1 answer:
Gennadij [26K]2 years ago
5 0

An error was made, correlation values can't be greater than 1.00.

The strength of the linear association between two variables is quantified by the correlation coefficient. The correlation coefficient always takes a value between -1 and 1. The 1 represents the perfect positive correlation and -1 represents the perfect negative correlation whereas the 0 represents the no correlation between two variables.

So, if the value of the correlation coefficient between shoe size and IQ is r = +1.99 then,

Analysts in some fields do not consider a correlation significant until the value is at least 0.8. However, a correlation coefficient with an absolute value of 0.9 or greater indicates a very strong relationship. 2.

Learn more about correlation values here: brainly.com/question/4219149

#SPJ4

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velikii [3]

Answer:

w = 12

Step-by-step explanation:

We are given the equation:

\displaystyle{\dfrac{w-2}{4} = \dfrac{2w+1}{10}}

First, clear out the denominators by multiplying both sides by LCM. In this scenario, our LCM is 40. Thus, multiply both sides by 40:

\displaystyle{\dfrac{w-2}{4} \cdot 40= \dfrac{2w+1}{10} \cdot 40}

Simplify the expressions/equations:

\displaystyle{(w-2)\cdot 10= (2w+1)\cdot 4}\\\\\displaystyle{10w-20= 8w+4}

Isolate w-variable:

\displaystyle{10w-20= 8w+4}\\\\\displaystyle{10w-8w=4+20}\\\\\displaystyle{2w=24}\\\\\displaystyle{w=12}

Hence, the solution is w = 12

If you have any questions regarding my answer or explanation, do not hesitate to ask away in comment!

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1 year ago
Marvin Martian, Aly Alien, and Hank Human are all looking for a hidden spaceship. Their probabilities of finding the spaceship f
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3 years ago
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Use the disk method or the shell method to find the volumes of the solids generated by revolving the region bounded by the graph
diamong [38]

Answer:

a) 8π

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Step-by-step explanation:

Given lines :  y = √x, y = 2, x = 0.

<u>a) The x-axis </u>

using the shell method

y = √x = , x = y^2

h = y^2 , p = y

vol = ( 2π ) \int\limits^2_0 {ph} \, dy

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p = 2 - y

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vol = ( 2π ) \int\limits^2_0 {ph} \, dy

     = ( 2\pi ) \int\limits^2_0 {(2-y).y^2} \, dy

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∴ Vol  = 8/3 π

<u>c) The y-axis  ( using shell method )</u>

h = 2-y  = h = 2 - √x

p = x

vol = (2\pi ) \int\limits^4_0 {ph} \, dx

     = (2\pi ) \int\limits^4_0 {x(2-\sqrt{x}  ) } \, dx

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p = 1 + x

h = 2√x

vol = (2\pi ) \int\limits^4_0 {ph} \, dx

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attached below is the graphical representation of P and h

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