A rectangle has a perimeter 204 it’s length six feet longer than twice it’s width if L stands for the rectangle and W stands for
its width, write a system of equations that models the information given in this problem and solve it to find the length and width of this rectangle.
1 answer:
Answer:
W=32
L=70
Step-by-step explanation:
L=2w+6
204=2L+2W
204=2w+2(2w+6)
204=2w+4w+12
192=6w
w=32
L=2(32)+6
L=70
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