Lcm of 63, 80 and 102

Help please! How would I solve a 2 step equation like this? 4(x-2)=14

sattari [20]

Answer: Hi!

Okay. So this equation we will solve using something called the distributive property. We use the distributive property to multiply the terms inside the parentheses (x and -2) by the term outside and in front of the parentheses (4). First, we would multiply 4 * x, which is 4x. Then, we would multiply 4 * -2, which is -8. Out equation now looks like this:

4x - 8 = 14

Our goal is to isolate the x, so now we'll use inverse operations to remove the -8 from the equation. The inverse operation for subtraction is addition, so we would add 8 to both sides:

4x - 8 = 14

+ 8 + 8

The eights cancel out, so we're left with this equation:

4x = 22

Last step! We're almost done. All we have to do now is divide 4 on both sides; in the term 4x, 4 is being multiplied by x, so the inverse operation would be division.

4x ÷ 4 = x

22 ÷ 4 = 5.5

Our equation now looks like this:

x = 5.5

So, 5.5 is equal to x! This would be your answer!

Hope this helps!

6 0

3 years ago

When purchasing bulk orders of batteries, a toy manufacturer uses this acceptance sampling plan: Randomly select and test 56 b

nydimaria [60]

Answer:

98.1% chance of being accepted

Step-by-step explanation:

Given:

sample size,n=56

acceptance condition= at most 2 batteries do not meet specifications

shipment size=7000

battery percentage in shipment that do not meet specification= 1%

Applying binomial distribution

In this formula, a is the acceptable number of defectives;

n is the sample size;

p is the fraction of defectives in the population.

Now putting the value

a= 2

n=56

p=0.01

$\frac{56!}{0!\left(56-0\right)!}\left(0.01\right)^0\:\left(1-0.01\right)^{\left(56-0\right)} + \frac{56!}{1!\left(56-1\right)!}\left(0.01\right)^1\:\left(1-0.01\right)^{\left(56-1\right)} +$ $\:\frac{56!}{2!\left(56-2\right)!}\left(0.01\right)^2\:\left(1-0.01\right)^{\left(56-2\right)}$

=0.56960+0.32219+0.08949

After summation, we get 0.981 i.e. a 98.1% chance of being accepted. As this is such a high chance, we can expect many of the shipments like this to be accepted!

7 0

3 years ago

Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-

Shtirlitz [24]

Answer:

The number c is 2.

Step-by-step explanation:

Mean Value Theorem:

If f is a continuous function in a bounded interval [0,4], there is at least one value of c in (a,b) for which:

$f(c) = \frac{1}{b-a}\int\limits^a_b {f(x)} \, dx$