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valentina_108 [34]
2 years ago
15

If Fred’s age now is three times what it was 12 years ago, how old is Fred 12 years ago?

Mathematics
1 answer:
Nikitich [7]2 years ago
6 0

Answer:

6

Step-by-step explanation:

12+x=3x

2x=12

x=6

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19/x=sin 20
19/sin 20=x
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your gas bill went up from $125 per month to $150 per month. what is the percent increase of your gas bill?
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Step-by-step explanation: what you need to do is take $150 and take $125 dollars away you will get $25!

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At 7:00 A.M., Alicia pours a cup of tea whose temperature is 200°F. The tea starts to cool to room temperature (72°F). At 7:02 A
NeTakaya

Answer:

Part A

The most correct option is;

b. y = 128(0.989)x + 72

Part B

Ella can drink the tea after 7:22

Step-by-step explanation:

Here we have the temperature variation with time given in an exponential equation as follows;

Let the temperature at time x (in minutes) = y

Therefore, y = a × mˣ + b

Where:

b = Shift of the curve or the limit value of the decreasing exponential function as x → ∞

When y = 200, x = 0

Therefore. 200 = a × m⁰ + c = a + c

We note that c is the shift of the graph, the value upon which temperature increases = final temperature = 72°F

Hence a = 200 - 72 = 128°F

When y = 197, x = 2 minutes

Therefore, 197 = 128·m² + 72 =

m² = (197 - 72)/128 = 125/128

m = √(125/128) = 0.98821

Hence the exponential equation of cooling is presented in the following equation;

y = 128 × (0.98821)ˣ + 72

Therefore, the most correct option is b. y = 128(0.989)x + 72

Part B

When the temperature is 172°F we have;

172 = 128 × (0.989)ˣ + 72

∴ (0.989)ˣ = (172 - 72)/128 = 100/128 = 25/32

log(0.989)ˣ = log(25/32)

x·log(0.989) = log(25/32)

x = log(25/32)/log(0.989) = 22.32 minutes

Hence Ella can drink the tea after 7:22.

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3 years ago
In the picture below, which segment is parallel to AD
Roman55 [17]

Answer:

BC

Step-by-step explanation:

because they never intersect each other

7 0
3 years ago
May someone help me with this problem?
Katyanochek1 [597]

Answer:

a. \:  \:  \frac{ {4x}^{6} }{ {y}^{3} }  \\

b. \:  \:  \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } }  \\

Step-by-step explanation:

<h3>a. </h3>

{( {4x}^{ - 2} y)}^{ - 3}  \\  {4x}^{ - 2 \times  - 3}  \:  \: {y}^{1 \times  - 3}  \\  {4x}^{6}  {y}^{ - 3}  \\  \frac{ {4x}^{6} }{ {y}^{3} }  \\

<h3>b.</h3>

{( {8x}^{6} {y}^{ - 3})  }^{ \frac{1}{2} }  \\  {8x}^{6 \times  \frac{1}{2} } \:  \:  {y}^{ - 3 \times  \frac{1}{2} }   \\  {8x}^{3}  {y}^{  - \frac {3}{2} }  \\  \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\

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2 years ago
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