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DochEvi [55]
2 years ago
10

A college is hosting an invention camp for middle school students. One of the 1,200 students who attend will receive a laptop at

the
end of the camp. The college wants to place notecards labeled with each student's name in a bin and draw a winner from the bin. The
bin will hold only 200 notecards though.
Which method assures both that the college can use the bin for the drawing and that each student has a fair chance of winning?
Place notecards labeled with the names of the oldest 200 students into the bin. Randomly select the winner from the bin.
O Place notecards labeled with the names of the first 200 students who registered for the camp into the bin. Randomly
select the winner from the bin.
Randomly assign the 1,200 students to 10 equal-sized groups. Then randomly select 4 of the groups and place their
names in the bin. Randomly select the winner from the bin.
Randomly assign the 1,200 students to 6 equal-sized groups. Then select one of the groups and place their names in the
bin. Randomly select the winner from the bin.
Mathematics
1 answer:
Ipatiy [6.2K]2 years ago
7 0

Answer: Randomly assign the 1,200 students to <u>6 equal-sized</u> groups. Then select one of the groups and place their names in the bin. Randomly select the winner from the bin.

Step-by-step explanation:

     First, let us see how many bins we will need in total.

1,200 students / 200 notecards per bin = 6 bins

     Now, the first two options do not give all students a fair chance of winning. They are not our answer.

     The last two have a different number of groups. Looking at the calculation we did earlier, we will need 6 equal-sized groups. This means our answer is the last option.

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Answer:

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Step-by-step explanation:

When dealing with consecutive integers, it often simplifies the problem to work with their average value. We know the average value of the integers in this problem is the even integer between the middle two. We can call it x, and write the equation ...

  (x-3) +(x-1) +(x+1) +(x+3) = -72

This simplifies to ...

  4x = -72 . . . . . . . we knew this before we wrote the above equation, since the sum of 4 numbers is 4 times their average.

  x = -18 . . . . . . . . the middle number of the sequence

So, the numbers are:

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_____

A more conventional approach is to define the variable as the integer at one end or the other of the sequence. If we make it be the lowest number, then the equation is ...

  (x) +(x +2) +(x +4) +(x +6) = -72

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Now, the other three numbers are found by adding 2, 4, and 6 to this one.

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