Area of a rectangle of length L and width W is A = LW.
Here, A = 60 ft^2 = (12 ft)(2x-3 ft). Let's find the values of x for which the area =60 ft^2, and then the values of x for which the area is greater than 60 ft^2.
60 = 12(2x-3) becomes 5 = 2x - 3 after dividing both sides by 12.
Adding 3 to both sides of this last equation results in 8 = 2x, so x = 4.
Does (12 ft)(2[4 ft] - 3) = 60? Does (12 ft)(5 ft) = 60 sq ft? YES.
The area of this rectangle will be greater than 60 sq ft if x>4 ft. (answer)
Answer:
Tessa receives £60
Step-by-step explanation:
The ratio is 5:3 so 5+3=8 which is then what you use to divide 96
96/8=12
12x5(the 5 comes from the ratio for Tess) is 60 therefore she receives £60
Answer:
10+12.50h=5+15h
We move all terms to the left:
10+12.50h-(5+15h)=0
We add all the numbers together, and all the variables
12.50h-(15h+5)+10=0
We get rid of parentheses
12.50h-15h-5+10=0
We add all the numbers together, and all the variables
-2.5h+5=0
We move all terms containing h to the left, all other terms to the right
-2.5h=-5
h=-5/-2.5
h=+2
Step-by-step explanation:
please heart and give brainliest
5 cm since a pentagon has 5 sides just multiply one side by 5
1x5=5
Answer:
Step-by-step explanation:
2x + 2 -3x -15 > 0
-x-13 > 0
-x > 13
Answer: x < -13
