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1 year ago

A food provides enough energy to raise the temperature of 2000 grams of water by 10°c. how many kilocalories does it contain?

Chemistry

1 answer:

Musya8 [376]1 year ago

5 0

A food provides enough energy to raise the temperature of 2000 grams of water by 10°c contains 20 KCa.

1 Calorie is the amount of heat needed to elevate one gram of water to one degree Celsius temperature at one atmosphere of pressure.

The term "kilocalorie" is used to describe the amount of energy needed to increase 1 L of water's temperature by one degree Celsius at sea level.

Given

Mass of water (m) = 2000 g
Temp raise (ΔT) = 10°C

Heat capacity of water (C) = 1 calorie/g-C

Formula used

Heat (ΔH) = m × C × ΔT

= 2000 × 10 = 20000 C

In Kilo calories

20000 C = 20000/1000 = 20 KCa

Hence, a food provides enough energy to raise the temperature of 2000 grams of water by 10°c contains 20 KCa.

Learn more about Calories here brainly.com/question/23688200

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Read 2 more answers

100.0 g of 4.0°C water is heated until its temperature is 37.0°C. If the specific heat of water is 4.184 J/g°C, calculate the am

Lady bird [3.3K]

Answer:

13.8072 kj

Explanation:

Given data:

Mass of water = 100.0 g

Initial temperature = 4.0 °C

Final temperature = 37.0°C

Specific heat capacity = 4.184 j/g.°C

Heat absorbed = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 37.0°C - 4.0 °C

ΔT = 33.0°C

Q = 100.0 g ×4.184 j/g.°C × 33.0°C

Q = 13807.2 j

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2 years ago

You have 345 mL of a 2.5 M NaCl solution. If you boil the water until the volume of the solution is 250 mLwhat will the molarity

HACTEHA [7]

The molarity of the solution will be 3.45 M

<h3>Further explanation </h3>

Dilution is the process of adding a solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution

V₁ = volume of the solution before dilution

M₂ = Molarity of the solution after dilution

V₂ = Molarity volume of the solution after dilution

The initial solution

345 mL of a 2.5 M NaCl solution.

M₁=2.5 M

V₁=345 ml

The solution after boiled :

V₂=250 ml

$\tt M_2=\dfrac{M_1.V_1}{V_2}\\\\M_2=\dfrac{2.5\times 345}{250}\\\\M_2=3.45~M$

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2 years ago