How many three-digit positive integers have three different digits and at least one prime digit?
1 answer:
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<u><em>Answer:</em></u>
m∠4 = 23°
<u><em>Explanation:</em></u>
<u><em>1- getting the value of x:</em></u>
<u>We know that KM bisects ∠NKL, this means that:</u>
∠3 = ∠4 = x
Now, we know that ∠NKJ, ∠3 and ∠4 form <u>a straight angle</u>.
This means that their summation is 180°
<u>We can now get the value of x as follows:</u>
180 = ∠NKJ + ∠3 + ∠4
180 = 5x + 19 + x + x
180 = 7x + 19
180 - 19 = 7x
161 = 7x
x = 23
<u><em>2- getting ∠4:</em></u>
From part 1, we got that x = 23
We are given that:
∠4 = x
This means that:
∠4 = 23°
Hope this helps :)
<u><em>Answer:</em></u>
m∠4 = 23°
<u><em>Explanation:</em></u>
<u><em>1- getting the value of x:</em></u>
<u>We know that KM bisects ∠NKL, this means that:</u>
∠3 = ∠4 = x
Now, we know that ∠NKJ, ∠3 and ∠4 form <u>a straight angle</u>.
This means that their summation is 180°
<u>We can now get the value of x as follows:</u>
180 = ∠NKJ + ∠3 + ∠4
180 = 5x + 19 + x + x
180 = 7x + 19
180 - 19 = 7x
161 = 7x
x = 23
<u><em>2- getting ∠4:</em></u>
From part 1, we got that x = 23
We are given that:
∠4 = x
This means that:
∠4 = 23°
Hope this helps :)