Qn. 1
Lower bound for Zoe's weight = 62 - (1/2) = 62 - 0.5 = 61.5 kg
Qn. 2
Upper bound for length AB = 8.3+ (0.1/2) = 8.3+0.05 = 8.35 cm
Qn. 3
Upper bound for Anu's wight = 83+(0.5/2) = 83+0.25 = 83.25 kg
Qn. 4
Lower bound for length CD = 27-(0.5/2) = 27-0.25 = 26.75 cm
Qn. 5
Upper bound for sides of the hexagon = 3.6+(0.1/2) = 3.6+0.05 = 3.65 cm
Upper bound for the perimeter = upper bound for the sides*6 = 3.65*6 = 21.9 cm
Qn. 6
Perimeter = 4*length => side = Perimeter/4 = 24/4 = 6
Bound = 0.5/4 = 0.125
Lower bound of the length = 6-0.125 = 5.875 cm
Qn. 7
For the area,
Upper bound = 80+(10/2) 80+5 = 85 cm^2
For the length
Upper bound = 12+(1/2) = 12+0.5 = 12.5
Then, upper bound for the width = Upper bound for the area/upper bound for the length = 85/12.5 = 6.8 cm
Qn. 8
Lower bound for the area = 230-(1/2) = 230-0.5 = 229.5 cm^2
Lower bound for the sides of the square = Sqrt(Lower bound of the area) = Sqrt (229.5) = 15.15
Then,
Lower bound of perimeter = 4(Length) = 4*15.15 = 60.6 cm
Since 470/6 = 78.333 it would take you 78.333 days to work 470 hours.
Answer:
This equation is in standard form: ax 1+bx+c=0. Substitute 9 for a, 16 for b, and −112 for c in the quadratic formula 2a−b±b2−4ac.x= 2×9−16± 16^2−4×9(−112)Square 16.x=2×9−16±256−4×9(−112) Multiply −4 times 9.x=2×9−16± 256−36(−112) Multiply −36 times −112.x=2×9−16±256+4032 Add 256 to 4032.x=2×9−16±4288 Take the square root of 4288.x=2×9−16±8+67 Multiply 2 times 9x=18−16±8=67
Step-by-step explanation:
hope this help if not let me know
First you must know that for remarkable angles: cos (0) = 1, cos (π) = - 1, cos (π / 2) = 0, cos (3π / 2) = 0, cos (2π) = 1. Then, by simple substitution in the given formula, you can find the solutions of x. Which for the interval [0, 2π) are: x = π, x = pi divided by two and x = three pi divided by two.Attached solution.
