The equations exist and then the value of
x = -6, x = -2 and y = -15, y = 1.
<h3>
How to solve the system of equations and </h3>
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The given equations are and
Subtract 9 from both sides, we get
Simplifying the equation, we get
Subtract 4x from both sides
Solve with the quadratic formula
Separate the solutions
The solutions to the quadratic equation are x = -6, x = -2
From the above equation ,
substitute the value of x, then we get
Put, x = -6 then y = 4(-6) + 9 = -15
Put, x = -2 then y = 4(-2) + 9 = 1
The system of equations exists (–2, 1) and (–6, –15).
Therefore, the correct answer is (–2, 1) and (–6, –15).
To learn more about quadratic equations refer to:
brainly.com/question/1214333
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