<span> An internet </span>company charges<span> $30 a </span>month<span>. There is also a $30 </span>installation fee<span>. Is the </span>number<span>of </span>months<span> you can </span>have<span> internet </span>proportional<span> to the total </span>cost<span>? Algebra. You are choosing </span>between two<span> different internet providers. </span>Company<span> A </span>charges<span> $75 for </span>installation<span> and $42 </span>per month.Company B charges<span> $30 </span>per<span> ...</span>
First try to isolate the variable, in this case "y". the first step to this is add 5/6 to both sides to get 5y/42=5/6. next multiply each side by 42 to get 5y=35. next divide by 5 to get y=7. so y=7 is the answer.
Given:
261 for 3 nights.
Find the cost for a 7 night stay.
We need to get the unit rate.
261 ÷ 3 nights =<span> </span>87 per night
87 x 7 nights = 609 for a 7 night stay.
If there are that many things missing then go left to right; 5+1 then multiply the sum by ten
5+1=6
6x10=60
I hope I was helpful
Step-by-step explanation:
5x-16 = 3 (10+x)
=> x= 23
