Answer:
width of the rectangle=x=4in and length of the rectangle=11in
Step-by-step explanation:
Let the width of the rectangle be x, then according to the question, length is one less than three times its width that is l=3x-1.
Now, width=b=x and length=l=3x-1, thus
Perimeter of the rectangle= 2(l+b)
⇒
⇒
⇒
⇒
⇒
Thus, width of the rectangle=x=4in and length of the rectangle=l=3x-1=3(4)-1=12-1=11in.
 
        
             
        
        
        
Answer:
if you're multiplying them it's c
Step-by-step explanation:
4.7•8.8=41.36
 
        
             
        
        
        
The bag contains,
Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4, 
Total marbles (possible outcome) is,

Let P(R) represent the probablity of picking a red marble,
P(G) represent the probability of picking a green marble and,
P(B) represent the probability of picking a blue marble.
Probability , P, is,


Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,
That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

Hence, the best option is G.
 
        
             
        
        
        
To solve this problem, let us first remember that
probability is:
Probability = number of successful events / number of total
events
 
Now, let us first calculate the probability of getting a
blue marble. There are 20 blue marbles out of 50 total marbles, therefore the
probability is:
P (blue marble) = 20 / 50 = 0.4
 
Next, let us calculate for the probability of landing tails
up. There are 22 tails success out of 50 times the coin was tossed, therefore
the probability is:
P (tails) = 22 / 50 = 0.44
 
Finally, since we want to find the Probability of getting
blue and Probability of landing tails, we multiply the two:
P (blue and tails) = 0.4 * 0.44
P (blue and tails) = 0.176               (ANSWER)
 
Now if the choices are in fraction:
P (blue and tails) = (20 / 50) (22 / 50) = 440 / 2500