8/11 = 0.72727273
So do 0.85 - 0.72727273
= 0.12272727
Answer:
The probability that sample mean differ the true greater than 2.1 will be 2.8070 %
Step-by-step explanation:
Given:
Sample mean =46 dollars
standard deviation=8
n=53
To Find :
Probability that sample mean would differ from true mean by greater than 2.1
Solution;
<em>This sample distribution mean problem,</em>
so for that
calculate Z- value
Z=(sample mean - true mean)/(standard deviation/Sqrt(n))
Z=-2.1/(8/Sqrt(53))
Z=-2.1*Sqrt(53)/8
Z=-1.91102
Now for P(X≥2.1)=P(Z≥-1.91102)
Using Z-table,
For Z=-1.91
P(X>2.1)=0.02807
Solution:
1/3+3 1/3
1/3+10/3
Answer: 11/3 simplified form 3 2/3
Double then triple both the numerator and denominator
remember any number divide by itself is 1(value will not change)
188/11 x 2/2= 376/22
188/11 x 3/3= 564/33
they all reduce to 188/11= 17.09
hope this helps
Answer:
24
Step-by-step explanation:
h=11
2*11=22
22+11=33