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IRINA_888 [86]
2 years ago
6

The amount you pay for a car is not usually the​ "sticker price," which may be the starting price. The price of a car was reduce

d by​ $300 from the sticker​ price, increased by​ $900 for additional​ features, and then reduced by​ $600 by the dealer. What integer represents the total change in price with respect to the sticker​ price? Use a number line to represent the change from the sticker price.
Mathematics
1 answer:
OLEGan [10]2 years ago
8 0

There will be no change in the price of the car.

<h3>What is a number line?</h3>

A number line is a representation of a graduated straight line used to abstract real numbers in elementary mathematics. Its points are considered to correspond to real numbers and vice versa.

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Let the sticker price = x, Price reduced by $300

Hence the new price is,

N= x-$300

The cost of additional features = $900

Hence the new price for selling will be.

=x-$300+$900

=x+$600

Dealer also provides a discount of $600

Hence Final  selling price will be

=x+$600-$600

Hence there seems to be no change in the sticker price as the sticker price and the final selling price are the same.

To know more about number line follow

brainly.com/question/24644930

#SPJ1

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An urn contains two blue balls (denoted B1 and B2) and three white balls (denoted W1, W2, and W3). One ball is drawn, its color
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Answer:

(a) Shown below.

(b) The probability that the first ball drawn is blue is 0.40.

(c) The probability that only white balls are drawn is 0.36.

Step-by-step explanation:

The balls in the urn are as follows:

Blue balls: B₁ and B₂

White balls: W₁, W₂ and W₃

It is provided that two balls are drawn from the urn, with replacement, and their color is recorded.

(a)

The possible outcomes of selecting two balls are as follows:

B₁B₁          B₂B₁          W₁B₁          W₂B₁          W₃B₁

B₁B₂         B₂B₂          W₁B₂         W₂B₂          W₃B₂

B₁W₁         B₂W₁         W₁W₁         W₂W₁         W₃W₁

B₁W₂        B₂W₂         W₁W₂        W₂W₂         W₃W₂

B₁W₃        B₂W₃         W₁W₃        W₂W₃         W₃W₃

There are a total of N = 25 possible outcomes.

(b)

The sample space for selecting a blue ball first is:

S = {B₁B₁, B₁B₂, B₁W₁, B₁W₂, B₁W₃, B₂B₁, B₂B₂, B₂W₁, B₂W₂, B₂W₃}

n (S) = 10

Compute the probability that the first ball drawn is blue as follows:

P(\text{First ball is Blue})=\frac{n(S)}{N}=\frac{10}{25}=0.40

Thus, the probability that the first ball drawn is blue is 0.40.

(c)

The sample space for selecting only white balls is:

X = {W₁W₁, W₂W₁, W₃W₁, W₁W₂, W₂W₂, W₃W₂, W₁W₃, W₂W₃, W₃W₃}

n (X) = 9

Compute the probability that only white balls are drawn as follows:

P(\text{Only White balls})=\frac{n(X)}{N}=\frac{9}{25}=0.36

Thus, the probability that only white balls are drawn is 0.36.

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