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vovikov84 [41]
1 year ago
11

Where do i put it? i dont remember how to do this

Mathematics
1 answer:
babymother [125]1 year ago
7 0

Answer:

y>=14

Step-by-step explanation:

y is the age, and you must be older than or as old as 14.

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Which graph represents the following system of inequalities.
Marta_Voda [28]

Answer: Graph C is correct

Step-by-step explanation:

The region below the dashed red line is y < 4/3x +2

The region below the solid purple line is y ≤ -1

The region below and left of the solid green line is y ≤ -3x

4 0
3 years ago
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!Simplify the following expression: (52)^8
liberstina [14]

Answer: brainly.com/question/27247548?answeringSource=feedPublic%2FhomePage%2F6https://brainly.com/question/27247548?answeringSource=feedPublic%2FhomePage%2F6https://brainly.com/question/27247548?answeringSource=feedPublic%2FhomePage%2F6

4 0
2 years ago
Read 2 more answers
7/8 - 5/12 ayudaaa por favor es para mañana​
RUDIKE [14]
7/8 = 21/24
5/12 = 10/24

21/24-10/24 = 11/24
3 0
2 years ago
THE vertices of a triangle are P(-1,3), Q(2,-1), and R(5,3) choose all the congruent sides of the triangle
Ratling [72]

Answer:

PQ and QR are congruent.

Step-by-step explanation:

The length of PQ = sqrt [(2 - -1)^2 + (-1 - 3)^2]

= sqrt 25

= 5 units.

QR = sqrt [(5-2)^2 + (3 - -1)^2) ]

= sqrt 25

= 5 units.

PR =  sqrt [ ( 3-3^2 + (5- -1)^2]

= sqrt 36

= 6 units.

7 0
3 years ago
Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5
givi [52]
<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]                            X=\left[\begin{array}{c}x\\y\end{array}\right]

and          B= \left[\begin{array}{c}11\\5\end{array}\right]

∴AX=B

adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]

A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6

∴A^{-1} =\frac{adj A}{|A|}

So,A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}

A^{-1} ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}

X =A^{-1}\times B

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c}  {6}\\  {11} \end{array}\right]}

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0
2 years ago
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