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2 years ago

I have 90% after about 75%

Mathematics

1 answer:

kkurt [141]2 years ago

6 0

The lowest grade he could earn is 120% of the grade at the end of the semester.

The following statement is given:

I have 90% after about 75% of the semester.

We are asked to find the lowest grade by the end of this semester.

<h3>What is Percentage?</h3>

A percentage is a number expressed as a fraction of 100.

- 50% = 50/100 = 1/2

- 25% = 25/100 = 1/4

- 20% = 20/100 = 1/5.

We can write this statement "I have a 90% grade after about 75% of the semester" as:

90% grade = 75% semester.............(1)

By the end of the semester means at 100% semester.

Multiplying equation (1) by 100/ 75 on both sides of the equation.

We get,

(100/75) x 90% grade = (100/75) x 75% semester

(100 x 90)/75 % grade = 100% semester

120% grade = 100%

Thus the lowest grade he could earn is 120% of the grade at the end of the semester.

Learn more about Percentages here:

brainly.com/question/24159063

#SPJ1

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Answer:

the answers have been provided below

Step-by-step explanation:

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In answer to the question:

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A. The baby born in week 40 does since its z-score is smaller.

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3 years ago

A box of pencils costs $10.The total cost (c) as a function of the number of boxes (b) is expressed as c = f(b) = 10b. What is t

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Answer:

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A is correct

Step-by-step explanation:

A box of pencils costs $10

The total cost (c) as a function of the number of boxes (b) is expressed as

c = f(b) = 10b

The function, f(b) = 10b

b is independent variable and c is dependent variable.

For any function find domain using independent variable.

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3 years ago

An assembled product is built by 10 worker who coordinate their task. A total of 100 units will be made. Time records indicate t

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Answer:

a) 86%

b) 2nd unit = 82 hs.

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Step-by-step explanation:

We can model the learning curve for manufacturing the units as:

$t=aX^b$

where t is the time for the Xth unit, and a and b are parameters that we will calculate from the data,

We know that t(1)=95. Then, we have:

$t(1)=a\cdot 1^b=95\\\\a=95$

And we know that the fourth unit (X=4) take 71 hours to be completed (t(4)=71). Then, we can calculate the other parameter as:

$t(4)=95\cdot4^b=71\\\\4^b=71/95\approx 0.7473\\\\b\cdot ln(4)=ln(0.7473)\\\\b=ln(0.7473)/ln(4)=-0.291/1.386\\\\b=-0.21$

We have the model for the learning curve:

$t=95X^{-0.21}$

The learning rate percentage is calculated from the b parameter:

$b=\dfrac{ln(LRP)}{ln(2)}=-0.21\\\\\\ln(LRP)=-0.21*ln(2)=-0.21*0.693=-0.1455\\\\LRP=e^{-0.1455}=0.86$

The learning rate percentage is 86%.

b) The most likely times required for the 2nd and 3rd units are calculated with the model:

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c) If we use the model to calculate the time required for the 100th unit, we have:

$t(100)=95\cdot100^{-0.21}=95*0.38=36$

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Step-by-step explanation:

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