Question

An engineer is designing a runway for an airport. Several planes will use the runway and the engineer must design it so that it is long enough for the largest planes to become airborne before the runway ends. If the largest place accelerates at 3.30 m/s^2 and has a takeoff speed of 88.0 m/s then what is the minimum allowed length for the runway?

Answer 1

Answer:

d=117.33 m

Step-by-step explanation:

Initial velocity of planes, u = 0 (because they are at rest)

Acceleration, a = 3.3 m/s²

Final take off speed, v = 88 m/s

We need to find the minimum allowed length for the runway. Let it is d. d will be the distance. It can be calculated using third equation of motion as follows :

$v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}$

Putting all the values, we get :

$d=\dfrac{88^2-0^2}{2\times 33}\\\\d=117.34\ m$

Hence, the minimum allowed length for the runway is 117.33 m.