The total number of marks in the examination is <u>500 marks</u> when the passing percentage is 40%, and a candidate securing 190 marks, failed by 10 marks.
In the question, we are given that in an examination, a candidate has to secure 40 percent of the marks to pass.
We are asked the total number of marks in the examination if a candidate secured 190 marks and failed by 10 marks.
The marks secured by the candidate = 190 marks.
The marks which he failed by = 10 marks.
Thus, passing marks = 190 + 10 = 200 marks.
We assume the total marks to be x marks.
We are given that to pass, a candidate needs 40 percent of the total marks.
Thus, passing marks = 40% of x marks.
But, we calculated the passing marks to be 200 marks.
Thus, we get an equation,
40% of x = 200,
or, 40/100 * x = 200,
or, x = 200*100/40 = 500.
Thus, the total number of marks in the examination is <u>500 marks</u>, when the passing percentage is 40%, and a candidate securing 190 marks, failed by 10 marks.
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