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rjkz [21]
2 years ago
12

Find the value of sin J rounded to the nearest hundredth, if necessary. 12 13 K

Mathematics
1 answer:
Nina [5.8K]2 years ago
3 0

The value of the sine of the angle J is equal to 5 / 13 (approx. 0.38).

<h3>What is the measure of the missing angle?</h3>

The image attached aside shows us a <em>right</em> triangle with two known <em>side</em> lengths (JL, KJ) and a <em>angle</em> measure (m ∠ K). The measure of the <em>missing</em> angle can be found by using the <em>trigonometric</em> function of cosine:

cos m ∠ J = KJ / JL

cos m ∠ J = 12 / 13

m ∠ J = 22.620°

The measure of the angle J within the triangle JKL is approximately 22.620°.

And the sine of the angle J, which helds the same <em>positive</em> sign than cosine as the angle is in the first quadrant on <em>Cartesian</em> plane, is:

sin m ∠J = √(1 - cos² m ∠J)

sin m ∠J = √[1 - (12 / 13)²]

sin m ∠J = 5 / 13

The value of the sine of the angle J is equal to 5 / 13 (approx. 0.38).

To learn more on trigonometric functions: brainly.com/question/6904750

#SPJ1

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Assume there are 365 days in a year.
MissTica

Answer:

1) The probability that ten students in a class have different birthdays is 0.883.

2) The probability that among ten students in a class, at least two of them share a birthday is 0.002.

Step-by-step explanation:

Given : Assume there are 365 days in a year.

To find : 1) What is the probability that ten students in a class have different birthdays?

2) What is the probability that among ten students in a class, at least two of them share a birthday?

Solution :

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

Total outcome = 365

1) Probability that ten students in a class have different birthdays is

The first student can have the birthday on any of the 365 days, the second one only 364/365 and so on...

\frac{364}{365}\times \frac{363}{365} \times \frac{362}{365} \times \frac{361}{365}\times\frac{360}{365} \times \frac{359}{365} \times \frac{358}{365} \times \frac{357}{365} \times\frac{356}{365}=0.883

The probability that ten students in a class have different birthdays is 0.883.

2) The probability that among ten students in a class, at least two of them share a birthday

P(2 born on same day) = 1- P( 2 not born on same day)

\text{P(2 born on same day) }=1-[\frac{365}{365}\times \frac{364}{365}]

\text{P(2 born on same day) }=1-[\frac{364}{365}]

\text{P(2 born on same day) }=0.002

The probability that among ten students in a class, at least two of them share a birthday is 0.002.

6 0
3 years ago
A classroom board is 54 inches wide and 36 inches tall. Eva
Lady bird [3.3K]
<h3>Answer:  180 inches</h3>

Work Shown:

L = 54 = length

W = 36 = width

P = 2(L+W) ... perimeter of the rectangle

P = 2(54+36)

P = 2(90)

P = 180

She needs 180 inches of ribbon.

To convert to feet, divide by 12. So 180 inches = 180/12 = 15 feet.

8 0
2 years ago
What are the correct classifications for the polygon
Dmitry [639]
It’s convex hexagon
8 0
3 years ago
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All of the following fractions are proper fractions, except A.11/12 B.7/5 C.1/6 D.8/15
Aloiza [94]

answer:

A.7/5 is the correct answer because numerator is more than denominator.

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6 0
3 years ago
Jack is 4 times as old as lacey. 7 years ago the sum of their age was 61. how old are they now?
BaLLatris [955]
I am guessing Jack is 51 and Lacey is 17.

7 0
3 years ago
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