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Viefleur [7K]
3 years ago
9

Write an equation of the line that passes through (-6.0) and (0, – 24).​

Mathematics
2 answers:
Delicious77 [7]3 years ago
7 0

Answer:

y = -4x - 24

Step-by-step explanation:

y = mb + b, so look for then m = -4 so the equation is y = -4x - 24

slope = -24 - 0 / 0 + 6 so m = -4 and b = -24 since x = 0 at the y-intercept

Ipatiy [6.2K]3 years ago
4 0

Answer:

y = -4x - 24

Step-by-step explanation:

Firstly, figure out the slope. To do that, plug the coordinates in the formula.

y2 - y1 / x2 -x1

= -24 - 0 / 0 - (-6)

= -4

The slope is -4/1x.

To figure out the y-intercept, you need to plug one of the coordinates into

y = -4x + b

0 = -4(-6) + b

0 = 24 +b

-24 = b

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E=-24

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This graph represents a quadratic function. What is the function's equation written in factored form and in vertex form?
grigory [225]

Answer:

vertex form:  f (x) = 2 * (x - 2) ^ 2 - 8

factored form: f (x) = 2 * x * (x - 4)

Step-by-step explanation:

The first thing is to calculate the equation with its vertex form, we can calculate it knowing that it is formulated in the following:

f (x) = a * (x - h) ^ 2 + k

where

a is a coefficient

(h, k) is the vertex

Looking at the graph

The vertex is the point (2, -8), we replace and we are left with:

f (x) = a * (x - 2) ^ 2 - 8

Now, to calculate the value of the coefficient we are going to

mark a point on the graph

, we will select (0,0)

and replacing we have:

0 = a * (0 - 2) ^ 2 - 8

0 = 4 * a - 8

a = 8/4

a = 2

Therefore, we would be left with the equation of the function written in The first thing is to calculate the equation with its vertex form, we can calculate it knowing that it is formulated in the following:

f (x) = a * (x - h) ^ 2 + k

where

a is a coefficient

(h, k) is the vertex

Looking at the graph

The vertex is the point (2, -8), we replace and we are left with:

f (x) = a * (x - 2) ^ 2 - 8

Now, to calculate the value of the coefficient we are going to

mark a point on the graph

, we will select (0,0)

and replacing we have:

0 = a * (0 - 2) ^ 2 - 8

0 = 4 * a - 8

a = 8/4

a = 2

Therefore, we would be left with the equation of the function written in vertex form:

f (x) = 2 * (x - 2) ^ 2 - 8

Now for the factored form, we know it has the following structure:

f (x) = a * (x - x1) * (x - x2)

knowing that a is a coefficient

and that x1 and x2 are the zeros or x-intercepts of the function

Looking at the graph

The zeros or x-intercepts of the function are

x = 0 and x = 4

so

f (x) = a * (x - 0) * (x - 4)

f (x) = a * x * (x - 4)

To calculate the value of the coefficient a, we will take the point (2, -8), we replace:

-8 = a * 2 * (2 - 4)

-8 = 4 * a - 8 * a

4 * a = 8

a = 2

we replace and we have:

f (x) = 2 * x * (x - 4) and this would be the factored form of the equation

Now for the factored form, we know it has the following structure:

f (x) = a * (x - x1) * (x - x2)

knowing that a is a coefficient

and that x1 and x2 are the zeros or x-intercepts of the function

Looking at the graph

The zeros or x-intercepts of the function are

x = 0 and x = 4

so

f (x) = a * (x - 0) * (x - 4)

f (x) = a * x * (x - 4)

To calculate the value of the coefficient a, we will take the point (2, -8), we replace:

-8 = a * 2 * (2 - 4)

-8 = 4 * a - 8 * a

4 * a = 8

a = 2

we replace and we have:

f (x) = 2 * x * (x - 4) and this would be the factored form of the equation

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