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Viefleur [7K]
3 years ago
9

Write an equation of the line that passes through (-6.0) and (0, – 24).​

Mathematics
2 answers:
Delicious77 [7]3 years ago
7 0

Answer:

y = -4x - 24

Step-by-step explanation:

y = mb + b, so look for then m = -4 so the equation is y = -4x - 24

slope = -24 - 0 / 0 + 6 so m = -4 and b = -24 since x = 0 at the y-intercept

Ipatiy [6.2K]3 years ago
4 0

Answer:

y = -4x - 24

Step-by-step explanation:

Firstly, figure out the slope. To do that, plug the coordinates in the formula.

y2 - y1 / x2 -x1

= -24 - 0 / 0 - (-6)

= -4

The slope is -4/1x.

To figure out the y-intercept, you need to plug one of the coordinates into

y = -4x + b

0 = -4(-6) + b

0 = 24 +b

-24 = b

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Express the confidence interval 0.555 less than 0.777 in the form Modifying above p with caret plus or minus Upper E.
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Complete Question

Express the confidence interval 0.555 less than p less than  0.777 in the form Modifying above p with caret plus or minus Upper E.

Answer:

The modified representation is \r p \pm  E  = 0.666 \pm  0.111

Step-by-step explanation:

From the question we are told that

    The  confidence interval interval is  0.555 <  p <  0.777

Now looking at the values that make up  the up confidence interval we see that this is a symmetric  confidence interval(This because the interval covers 95%  of the area under the normal curve which mean that the probability of a value falling outside the interval is 0.05 which is divided into two , the first half on the left -tail and the second half on the right tail  as shown on the figure in the first uploaded image(reference - Yale University ) ) which means

     Now  since the confidence interval is  symmetric , we can obtain the sample proportion as follows

             \r p  =  \frac{0.555 + 0.777}{2}

            \r p  =0.666

Generally the margin of error is mathematically represented as

            E  =  \frac{1}{2}  *  K

Where  K is the length of the confidence interval which iis mathematically represented as

           K  =  0.777 -0.555

         K  = 0.222

Hence  

          ME  =  \frac{1}{2}  *  0.222

           ME  =  0.111

So the confidence interval can now be represented as

        \r p \pm  E  = 0.666 \pm  0.111

     

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