A. Would be your answer.
That is pretty much the exact definition of advance directive.
Hope I helped!
Answer:
A) 2.02 standard deviations from 600 - a win
B) The last interval was a close call.
Explanation:
n = 2300
p = 0.47, q = 1-p = 0.53
μ = np = 1081
σ = √(npq) = 23.94
Z.025 = 1.96
B) Finding both confidence interval:
Confidence Interval = (μ-1.96(23.94)/√2300, μ+1.96(23.94)/√2300)
= (1081 - 0.978, 1081 + 0.978)
= (1080.022, 1081.978)
(1080-600)/23.94 = 2.02 standard deviations from 600 - a win
B)
AS above
n=450, p=.54, q=.46
μ=np=243, σ=√(npq)=10.6
confidence interval (243-1.96(10.6)/√450 , 243+1.96(10.6)/√450)
= 243-.98, 243+.98) = (242.0, 243.98)
(244-225)/10.6=1.8 standard deviations from win
Give the picture. Because we don’t know what we did
The approximate latitude and longitude of the site is between 4°08' N, 35°54' E.
<h3>What is the
Nariokotome about?</h3>
The Nariokotome site is known to be located in northern Kenya,
Note that this site in northern Kenya was said to be discovered in 1984 and this was because of the discovery of a full skeleton of African Homo erectus.
Hence, The approximate latitude and longitude of the site is between 4°08' N, 35°54' E.
Learn more about Nariokotome from
brainly.com/question/28163982
#SPJ1
Answer:
sorry, i don't understand your question
Explanation:
write your questions properly then only i can help you!.
