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2 years ago

8

Find the mean for the data set. {222, 240, 220, 234, 202, 244, 226, 226, 214, 215, 196, 210, 191, 220, 225, 210, 229, 200, 236,

195, 205}

1 answer:

Nina [5.8K]2 years ago

8 0

Answer:

answer

Step-by-step explanation:

217.14285714285

do the step by step calculation yetself

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Scores for a standardized test are normally distributed with a mean of 350 and a standard deviation of 25. If 1793 students scor

Sergeu [11.5K]

Answer:

I think this is right 50 but I don't know I am 3rd grade

Step-by-step explanation:

<h2>so tha $so look 350 so minus that is 50$ s my answer</h2>

6 0

2 years ago

Suppose you spin the pointer on this spinner. (circle with 4 outcomes from 1 to 4). What is the probability the pointer does not

sveticcg [70]

The probability of getting 1,2,or 4 is .75 or 75%

8 0

3 years ago

Who can help asap!!

notka56 [123]

Answer:

0.33=33/100

<h2>Hope this helps!!!!!</h2>

4 0

3 years ago

Read 2 more answers

Equation of the line that passes through the point (4,–5) and is perpendicular to the line y=1/3x+5

fomenos

Answer:

y=1/3x+5 hope it helps you

5 0

3 years ago

Find f(g(x)). State the domain of the composite function.<br> f(x) = 3x-2/x+1<br> g(x) = x+5/2x-3

AnnyKZ [126]

Answer:

ℝ - {(-2/3),(3/2)}

Step-by-step explanation:

We want the domain of f(g(x)). So, firstly, we have to find the domain for g(x) and, then, for f(g(x)).

- Domain of g(x): Since the expression is a fracion, we must exclude the values of x that make null the denominator. Hence,

$g(x)=\dfrac{x+5}{2x-3}\Longrightarrow 2x-3\neq 0\iff \boxed{x\neq\dfrac{3}{2}}$

- Domain of f(g(x)): We'll find its expression:

$f(x) = \dfrac{3x-2}{x+1}\\\\f(g(x)) = \dfrac{3g(x)-2}{g(x)+1}\\\\f(g(x)) = \dfrac{3\cdot\dfrac{x+5}{2x-3}-2}{\dfrac{x+5}{2x-3}+1}=\dfrac{~~~\dfrac{3(x+5)-2(2x-3)}{2x-3}~~~}{\dfrac{(x+5)+(2x-3)}{2x-3}}\\\\f(g(x)) =\dfrac{3(x+5)-2(2x-3)}{(x+5)+(2x-3)}=\dfrac{3x+15-4x+6}{x+5+2x-3}\\\\\boxed{f(g(x)) =\dfrac{21-x}{3x+2}}$

Now, once again, we have to exclude the values of x that make the denominator equals to zero. Thus,

$f(g(x)) =\dfrac{21-x}{3x+2}\Longrightarrow 3x+2\neq0\iff \boxed{x\neq-\dfrac{2}{3}}$

Lastly, we may write the domanin of f(g(x)):

$D(f(g(x)) = \left]-\infty,-\dfrac{2}{3}\right[\cup\left]-\dfrac{2}{3},\dfrac{3}{2}\right[\cup\left]\dfrac{3}{2},\infty\right[$

or, just writing in a shorter way:

$\boxed{D(f(g(x)) = \mathbb{R}-\left\{-\dfrac{2}{3},\dfrac{3}{2}\right\}}$

7 0

2 years ago