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Vesna [10]
2 years ago
11

3x 2y = 4 2x - y = 5 this system of equations has no solution. has one solution. is coincident.

Mathematics
1 answer:
juin [17]2 years ago
7 0

Answer:

no solution

Step-by-step explanation: because if it has no variables that are the same it has no solution.

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Explain the steps you would take to find the area of the following composite shape. (Use 3.14 for TT.)
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pi r squared divided by 2 for the half circle then add the area of the box to you number and there is your area

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In my number the digit in the ones place is double the digit in the tens place. the sum of the digits is 3
jasenka [17]
The number is 21 because 2 is 1 doubled, and 2+1 is 3.
6 0
3 years ago
2. Check the boxes for the following sets that are closed under the given
son4ous [18]

The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

   a) Subtraction

   b) Addition

   c) AdditionSum

   d) in this case we have two possibilities

       * If we move to the right the addition

       * If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

        -3 -1 = -4

        -4 -1 = -5

        -7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) 0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}  ...

In this case we can see more clearly the sequence when writing in this way

      0, \sqrt{1^2}. \sqrt{2^2}, \sqrt{3^2 } . \sqrt{4^2} , \sqrt{5^2}

each term is found by adding 1 to the current term,

      \sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}

Therefore the mathematical operation is the addition

c)   ... \frac{-10}{2}. \frac{-8}{2}, \frac{-6}{2}, \frac{-4}{2}. \frac{-2}{2}. ...

      The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

  • To move to the right add 1

           -\frac{-10}{2} + 1 = \frac{-10}{2}  -   \frac{2}{2}  = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}

  • To move left subtract 1

         \frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}

         

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

   a) Subtraction

   b) Sum

   c) Sum

   d) This case we have two possibilities

  •  If we move to the right the sum
  •  If we move to the left we subtract

Learn more here: brainly.com/question/4626313

5 0
2 years ago
What is the answer to f(x)=x^2-10x+4 f(-2)
Maru [420]

Answer:

Step-by-step explanation:

f(x)=4+20+4

    =28

3 0
3 years ago
What is F(8) if f(x) = 15x
Lilit [14]

Answer:

F(8)=120

Step-by-step explanation:

f(x)=15x

f(8)=15(8)

f(8)=120

6 0
3 years ago
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