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daser333 [38]
3 years ago
6

What is 0.32 bar as a fraction

Mathematics
1 answer:
valentina_108 [34]3 years ago
3 0

.32 is 32/100

16/50

8/25 in simplest form

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Please someone help me with this ASAP especially with the workout!!
lara31 [8.8K]

Answer:

71 degrees

Step-by-step explanation:

please someone help me with this ASAP especially with the workout!!

From the triangle shown;

YX² = YZ² + XZ² - 2(YZ)(XZ) cos Z

28² = 25² + 23² - 2(25)(23) cos Z

784 = 625 + 529- 1150 cos Z

784 - 1154 = -1150cos Z

-370 = -1150cos Z

cos Z = 370/1150

cos Z = 37/115

cos Z = 0.3217

Z = arccos 0.3217

Z = 71.23

hence the measure of <Z is 71 degrees

3 0
3 years ago
URGENT PLEASE HELP!!!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (39pt
WITCHER [35]

Angle O=64

Side m=7.3159882(rounded if needed)

Side n=16.68902(round if needed)

We are given

Angle M which equal 26.

Angle N equals 90 degrees

Side MN which equal 15.

We are asked to find all the missing elements of the triangle.

  1. Angle O can be found using triangle interior theorem so we can add 90+26+x =180 to find the value that satisfies the x value.

90 + 26 + x = 180

116 + x = 180

x = 64

Angle O=64 degrees

We can find side m by doing law of sines.

\frac{on}{ \sin(26) }  =  \frac{mn}{ \sin(64) }

\frac{on}{ \sin(26) }  =  \frac{15}{ \sin(64) }

on =  \frac{15}{ \sin(64) }  \times  \sin(26)

which is 7.315(round if neeeded).

We can find side n using pythagorean theorem,

{15}^{2}  +  {7.3}^{2}  =  {n}^{2}

225 + 53.29 =  {n}^{2}

\sqrt{278.29}

Side n=16.689(round if needed)

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3 years ago
Simplify (10^-2)^4 djjdejieoeiieis
sergejj [24]

Answer:

10^-8

Step-by-step explanation:

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A gold mine has two​ elevators, one for equipment and another for the miners. The equipment elevator descends 4 feet per second.
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Let d_m,\ d_e represent the depth of the miner and equipments elevator, respectively. We know that equipment elevator descends with a velocity of v_e = 4 feet per second, and the miners one descends with a velocity of v_m = 15 feet per second.

If we start counting time (t=0) when the equipment elevator begins to descend, after t seconds its depth will be

d_e(t) = v_et = 4t

On the other hand, the miner elevator follows the same rule, but we have to use its velocity, and remember that it starts with a delay of thirty seconds:

d_m(t) = v_m(t-30) = 15(t - 30)

Now, we have to wait the 30 seconds of delay, and then another 14 seconds. This means that we want to know the positions of both elevators when t = 44. Let's plug this value into the two equations:

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Try describing the amount of numbers in the square u know like "shade covers 2/4 of the square''
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