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grin007 [14]
2 years ago
11

On December 1, 2020, Bramble Corporation incurs a 15-year $1300000 mortgage liability in conjunction with the acquisition of an

office building. This mortgage is payable in monthly installments of $15600, which include interest computed at the rate of 12% per year. The first monthly payment is made on December 31, 2020. The portion of the second monthly payment made on January 31, 2021, which represents repayment of principal is: $12974. $15600. $2626. $2600.
Business
1 answer:
weeeeeb [17]2 years ago
6 0

The portion of the second monthly payment made on January 31, 2021, which represents repayment of principal is $15600.

<h3>Mortgage liability </h3>

Mortgage liability limits the liability of potential third parties who were not involved when the mortgage was arranged. For example, if a mortgage is in arrears, the debtor has to pay the outstanding principal and interest, plus late payment and other charges.

<h3>What is mortgage asset or liabilities?</h3>

A current liability for

1) the principal payments that will be coming due within one year after the balance sheet date, and

2) any accrued interest that is owed as of the balance sheet date.

To learn more about current liability  visit the link

brainly.com/question/14287268

#SPJ4

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You plan to invest in bonds that pay 6.0%, compounded annually. If you invest $10,000 today, how many years will it take for you
kati45 [8]

Answer:

The answer is 16 years.

Explanation:

The formula for calculating the value of an investment that is compounded annually is given by:

V(n)=(1+R)^nP

Where:

n is the number of years the investment is compounded,

R is the annual interest rate,

P is the principal investment.

We know the following:

25000=(1+0.06)^n \times 10000

And we want to clear the value <em>n</em> from the equation.

The problem can be resolved as follows.

<u>First step:</u> divide each member of the equation by 10,000:

\frac{ 25000}{10000}=(1+0.06)^n \times \frac{ 10000}{10000}

2.5=(1.06)^n

<u>Second step:</u> apply logarithms to both members of the equation:

log(2.5)=log (1.06)^n

<u>Third step:</u> apply the logarithmic property logA^n=n.logA in the second member of the equation:

log(2.5)=n.log (1.06)

Fourth step: divide both members of the equation by log1.06

\frac{log(2.50)}{log (1.06)} =n

n= 15.7252

We can round up the number and conclude that it will take 16 years for $10,000 invested today in bonds that pay 6% interest compounded annually, to grow to $25,000.

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