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2 years ago

A man left rs 1,800,000 as inheritance.his heirs are 6 daughters and 2 sons.find the share of each heir

Mathematics

1 answer:

egoroff_w [7]2 years ago

3 0

Answer:$225,000 each

Step-by-step explanation: Assuming that they each get an equal share of the inheritance, there are 8 shares of the inheritance so we divided the $1.8m by 8 which equals $225,000 each.

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Answer:

x-intercepts: (-3.08, 0) and (1.08, 0)

Step-by-step explanation:

Given:

The function is given as:

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In order to find the x-intercept, we need to equate the given function to 0 as x-intercept is the point where the 'y' value is 0. So,

$y=0\\3x^2+6x-10=0$

Now, this is a quadratic equation of the form $ax^2+bx+c=0$

We find the solution using the quadratic formula,

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here, $a=3,b=6,c=-10$

Now, the solutions are:

$x=\frac{-6\pm \sqrt{6^2-4(3)(-10)}}{2(3)}\\\\x=\frac{-6\pm \sqrt{36+120}}{6}\\\\x=\frac{-6\pm \sqrt{156}}{6}\\\\x=\frac{-6}{6}-\frac{2\sqrt{39}}{6}\ or\ x=\frac{-6}{6}+\frac{2\sqrt{39}}{6}\\\\x=-1-2.08\ or\ x=-1+2.08\\\\x=-3.08\ or\ x=1.08$

Therefore, the x-intercepts are (-3.08, 0) and (1.08, 0)

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