The solution of are 1 + 2i and 1 – 2i
Solution:
Given, equation is
We have to find the roots of the given quadratic equation
Now, let us use the quadratic formula
--- (1)
Let us determine the nature of roots:
Here in a = 1 ; b = -2 ; c = 5
Since , the roots obtained will be complex conjugates.
Now plug in values in eqn 1, we get,
On solving we get,
we know that square root of -1 is "i" which is a complex number
Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i
Fourths, (1/4), (.25), (25%)
Answer:
Option A) m∠RNS=27°
Step-by-step explanation:
We know that 
∠UNR = 180°. This tells us that the Sum of the enclosed angles should equal 180°, by trigonometry. So the enclosed angles are:
∠RNS = 
∠SNT= 
∠TNU= 
Now let us add all the angles and solve for the value of 
as follow:
Now lets plug in the value into the expression for angle ∠RNS to find the angle as:
Thus Option A. is the correct answer.
Answer:
C. 1, -9
Step-by-step explanation:
I just put it on desmos
<span>A) 5x + 7y = 3
B) 2x + 3y = 1
Multiplying Equation B by -2.5
</span><span>B) -5x -7.5y = -2.5 Then adding this to Equation A)
A) 5x + 7y = 3</span>
-.5y = .5
y = -1
Since
<span>2x + 3y = 1 then
2x -3 = 1
then x = 2
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