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anyanavicka [17]
2 years ago
6

According to the bohr model, what determines the shortest wavelength in a given series of wavelengths emitted by the atom?

Chemistry
1 answer:
algol132 years ago
4 0

According to the bohr model "The lower energy level into which the electron deflects from a higher energy level is designated by the quantum number nf" determines the shortest wavelength in a given series of wavelengths emitted by the atom.

By explaining that electrons move in fixed orbitals (shells) and not anywhere in between, Bohr theory amended the atomic structure model.

He also showed that each orbit (shell) has a fixed energy. Bohr refined Rutherford's model of the atom's nucleus to include electrons and their varying energy levels.

According to Rydberg formula

1/λ = R [1/ni² - 1/nf²]

λ = wavelength

R = Rydberg constant

ni & nf are integers or principal quantum numbers where nf > ni

So if we want wavelength(λ) to be shortest, then 1/nf should be zero.

In this way , it depends on nf and not on ni

That's why the lower energy level into which the electron deflects from a higher energy level is designated by the quantum number nf" determines the shortest wavelength in a given series of wavelengths emitted by the atom.

Learn more about Bohr's model here brainly.com/question/18002213

#SPJ4

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$\Delta s_{water} = mc \ \ln\left(\frac{T_f}{T_i} \right)$

           $ = 130 \times 4.18\ \ln\left(\frac{33.63 + 273}{26 + 273} \right)$

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So, the total entropy change during the process is :

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$X=mc (T-T_0) - T_0 \ mc \ \ln \left(\frac{T}{T_0} \right)+0$

$X=mc\left((T-T_0)-T_0 \ ln \left(\frac{T}{T_0} \right)\right)$

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Therefore, energy of the combined system at the initial state is

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$X_{final}=X_{iron,f} +X_{water, f$

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$0-X_{destroyed} = $

$X_{destroyed} = X_{initial} - X_{final}$

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