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bogdanovich [222]
3 years ago
11

When a solution of iron(III) nitrate is mixed with a solution of sodium hydroxide, a rust colored precipitate forms. This precip

itate is probably When a solution of iron(III) nitrate is mixed with a solution of sodium hydroxide, a rust colored precipitate forms. This precipitate is probably a. iron (III) nitrate. b. sodium hydroxide. c. iron (III) hydroxide. d. sodium nitrate. e. none of the above
Chemistry
1 answer:
astraxan [27]3 years ago
3 0

Answer: c. iron (III) hydroxide

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

The balanced chemical equation for solution of iron(III) nitrate is mixed with a solution of sodium hydroxide is:

Fe(NO_3)_3(aq)+3NaOH(aq)\rightarrow Fe(OH)_3(s)+3Na(NO_3)(aq)

As iron(III) hydroxide is insoluble in water , it is formed as a solid which is called as precipitate.

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2 years ago
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Answer:

A. The final temperature of both substances is closer to the initial temperature of substance A than the initial temperature of substance B.

Explanation:

Given;

mass of substance A = mass of substance B = m

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final temperature of substance A = Tₐ

initial temperature of substance B = t_b

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Q_a = Q_b

M_ac_a(T_a-t_a) = M_bc_b(T_b-t_b)\\\\But, M_a = M_b, \ T_a =T_b, =T\ and , \ C_a = 3C_b\\\\ 3C_b(T-t_a) = c_b(T-t_b)\\\\ 3(T-t_a) = T-t_b\\\\3T -3t_a = T -t_b\\\\3T -T = 3t_a -t_b\\\\2T = 3t_a -t_b\\\\T = \frac{3t_a}{2} - \frac{t_b}{2} \\\\T = 1.5t_a - 0.5t_b

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