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2 years ago

Which describes the combined variation shown in the equation F = kxy/z?

Mathematics

1 answer:

Papessa [141]2 years ago

3 0

Answer:

option 4

Step-by-step explanation:

F = $\frac{kxy}{z}$

k is the constant of variation

• if the variables are on the numerator they vary directly

• if the variables are on the denominator they vary inversely

In this case F varies directly with x and y ( variables on numerator ) and inversely with z ( variable on denominator )

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Ratling [72]

Answer:

33.64

Step-by-step explanation:

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3 years ago

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disa [49]

The circle is open if the inequality is greater than (>) or less than (<) and closed if the inequality is greater than or equal to (≥) or less than or equal to (≤)
If the arrow points to the right (—>) towards bigger numbers, x (whatever number is on the line) will be GREATER (> or ≥)
If the arrow o points to the left (<—) towards smaller numbers, x will be LESSER (< or ≤)

1. Starts at -2 with a closed circle and goes in the positive direction —>
So x ≥ -2
2. Starts at 2 with an open circle and goes in the negative direction <—
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And the rest use the same method.

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3 years ago

Read 2 more answers

A caterer has 5 rolls. He is ordering more rolls. He can order up to 9 packages of rolls and each package contains 12 rolls. The

stich3 [128]

B is the practical domain of the function

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3 years ago

Find the value of the variable and YZ if Y is between X and Z. XY=4n+3, YZ=2n-7,XZ=22

ruslelena [56]

Answer:

$\large \boxed{n = \dfrac{13}{3}; YZ = \dfrac{5}{3}}}$

Step-by-step explanation:

I think you have the situation shown in the diagram below.

1. Calculate the value of n

$\begin{array}{rcl}XY + YZ & = & XZ\\4n+ 3 + 2n - 7 & = & 22\\6n - 4 & = & 22\\6n & = & 26\\n & = & \dfrac{26}{6}\\\\& = & \mathbf{\dfrac{13}{3}}\\\end{array}\\\large \boxed{\mathbf{n = \dfrac{13}{3}}}$

2. Calculate the value of YZ

$\begin{array}{rcl}YZ & = & 2n - 7\\& = & 2\left (\dfrac{13}{3}\right ) - 7 \\\\& = & \dfrac{26}{3} - 7\\\\& = & \dfrac{26}{3} - \dfrac{21}{3}\\\\& = & \dfrac{5}{3} \\\\\end{array}\\\large \boxed{YZ = \mathbf{ \dfrac{5}{3}}}$

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3 years ago

Pauline travels between two cities. First she drives for 40 minutes at an average speed of 88 km/hr then for 40 minutes at an av

Scilla [17]

Pauline's average speed for this trip is 64 km/hr.

Explanation

First we will convert each 'minutes' into 'hours' . So......

40 minutes = $\frac{40}{60}hours =\frac{2}{3} hours$ and 23 minutes = $\frac{23}{60}hours$

Now, $Distance = Speed* Time$

So, the distance traveled for first 40 minutes at 88 km/hr speed $=(88* \frac{2}{3})km = 58.67 km$ ,

the distance traveled for next 40 minutes at 75 km/hr speed $=(75*\frac{2}{3})km=50 km$ and

the distance traveled last 23 minutes at 49 km/hr speed $=(49*\frac{23}{60})km = 18.78 km$

So, the total distance traveled $=(58.67+50+18.78) km = 127.45 km$

She spends 17 minutes eating lunch and buying gas.

So, the total time taken for the trip $= (40+40+17+23)minutes = 120 minutes= 2 hours$

Thus, Pauline's average speed for this trip = (Total distance / Total time) $=(\frac{127.45}{2})km/hr = 63.725 km/hr =64 km/hr$ (Rounded to the nearest km/hr)

8 0

3 years ago