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Maru [420]
3 years ago
5

Nelly has a large rectangular postcard that is 9 inches long and 4 inches wide. What is the area of the postcard?

Mathematics
2 answers:
pshichka [43]3 years ago
3 0

The answer is probably 36

antoniya [11.8K]3 years ago
3 0

Answer:

The answer is 36 inches

Step-by-step explanation:

Since the rectangle is 9 inches long and the length is 4 inches wide and you need to find the area the formula is A=L*W so you would multiply 9 and 4 which gives you 36

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lidiya [134]

|2x - 1|  =  | - x - 2|

Thus ;

2x - 1 =  - x - 2

Add both sides x

2x + x - 1 =  - x + x - 2

3x - 1 =  - 2

Add both sides 1

3x - 1 + 1 =  - 2 + 1

3x =   - 1

Divide both sides by 3

\frac{3x}{3}  =  \frac{ - 1}{3}  \\

x =  -  \frac{1}{3}  \\

<h2>Or </h2>

2x - 1 =  - ( - x - 2)

2x - 1 = x + 2

Subtract both sides x

2x  - x  - 1 = x - x + 2

x - 1 = 2

Add both sides 1

x - 1 + 1 = 2 + 1

x = 3

There u go ...

3 0
2 years ago
PLEASE HELP!! WILL GIVE BRAINLIEST!!!
Murrr4er [49]

Answer:

option D

Step-by-step explanation:

Jerry solved this equation: 

3(x-\frac{1}{4})=\frac{13}{6}

In the first step , she multiplied 3 inside the parenthesis

1. 3x-\frac{3}{4}=\frac{13}{6}

In step 2, 3/4 is added on both sides

2. 3x-\frac{3}{4}+\frac{3}{4}=\frac{13}{6}+\frac{3}{4}

In step 3, we take LCD 12

3. 3x=\frac{26}{12}+\frac{9}{12}

In step 4, add the fractions

4. 3x=\frac{35}{12}

Here, 3 or 3/1 are same.

\frac{3}{1}x=\frac{35}{12}

In step 5, to remove 3/1 we multiply both sides by 1/3.

Instead of multiplying 1/3 , Jerry made an error by multiplying 3/1

\frac{1}{3} \cdot \frac{3}{1}x=\frac{1}{3} \cdot \frac{35}{12}

x=\frac{35}{36}

In step 5, he should have multiplied both sides by 1/3

7 0
3 years ago
Read 2 more answers
72.4 divided by 4 please help!!!!
wariber [46]

Answer:

18.1

hope it helps mate

8 0
3 years ago
Read 2 more answers
Can someone please answer this
kaheart [24]

Answer:

<h2>{7}^{3} (as \: a \: single \: power \: of \: 7)</h2>

Step-by-step explanation:

<em><u>Given</u></em><em><u> </u></em><em><u> </u></em>

{7}^{4}  \div 7

<em><u>Since</u></em><em><u>,</u></em>

{a}^{x}  \div  {a}^{y}  =  {a}^{x - y}

<em><u>Hence</u></em><em><u>,</u></em>

=  {7}^{4 - 3}

=  {7}^{3} (ans)(as \: a \: single \: power \: of \: 7)

8 0
2 years ago
P-21=34 P=34-21 P=13<br>What is the value of p?<br>​
vredina [299]

Simplifying

P + -21 + -21 = 34 + -21  

-21 + -21 + P = 34 + -21

Combine like terms: -21 + -21 = -42

-42 + P = 34 + -21

Combine like terms: 34 + -21 = 13

-42 + P = 13

Solving

-42 + P = 13

Solving for variable 'P'.

Move all terms containing P to the left, all other terms to the right.

Add '42' to each side of the equation.

-42 + 42 + P = 13 + 42

Combine like terms: -42 + 42 = 0

0 + P = 13 + 42

P = 13 + 42

Combine like terms: 13 + 42 = 55

P = 55

Simplifying

P = 55

3 0
3 years ago
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