Answer:
c.
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Answer:
equation
Step-by-step explanation:
Inverse operations are used to solve simple algebraic equations to more difficult equations that involve exponents, logarithms, and trigonometry. Mathematically, inverse operations are opposite operations. Addition is the opposite of subtraction; division is the opposite of multiplication, and so on.
[RevyBreeze]
This can be solved in two ways: With heavy tools or with just algebra.
What is your level? Have you studied calculus?
With pure algebra:
We need to find the maximum of the function <span>h = −16t^2 + 36t + 5
Lets take out -1 for simplicity:
</span><span>h = −(16t2 - 36t - 5)
For now lets just work with this: </span>16t^2 - 36t - 5
16t^2=(4t)^2
(4t-x)^2= 16t^2-2*4xt+x^2
we have -36t so x should be 4.5 as 2*4*4.5=36
Lets see what we have now:
16t^2 - 36t - 5= (4t-4.5)^2 is this true? No but close
(4t-4.5)^2= 16t^2- 2*4*4.5t +4.5^2= 16t^2-36t+20.25
16t^2 - 36t - 5 and 16t^2-36t+20.25 nearl the same just take away 25.25 from the right hand side
Getting long, just stay with me:
16t^2 - 36t - 5= (4t-4.5)^2 - 25.25
h= -{(4t-4.5)^2 -25.25}
h=-(4t-4.5)^2 + 25.25
We want to find the maximum of this function. -(4t-4.5)^2 this bit is always negative or 0, so it maximum is when it is 0. Solve: 4t-4.5=0
t=1,125
