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Diano4ka-milaya [45]
2 years ago
10

How do I do this!!!!!

Mathematics
1 answer:
Readme [11.4K]2 years ago
6 0

The expected values of the binomial distribution are given as follows:

1. 214.

2. 21.

3. 31.

<h3>What is the binomial probability distribution?</h3>

It is the <u>probability of exactly x successes on n repeated trials, with p probability</u> of a success on each trial.

The expected value of the binomial distribution is:

E(X) = np

For item 1, the parameters are:

p = 3/7, n = 500.

Hence the expected value is:

E(X) = np = 500 x 3/7 = 1500/7 = 214.

For item 2, the parameters are:

p = 0.083, n = 250.

Hence the expected value is:

E(X) = np = 250 x 0.083 = 21.

For item 3, the parameters are:

p = 1/13, n = 400.

Hence the expected value is:

E(X) = np = 400 x 1/13 = 31.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

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